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Lelu [443]
2 years ago
10

This is the change in kinetic energy of a system in which a 16 kg object moving at 25 m/s slows to a velocity of 20 m/s.

Mathematics
1 answer:
Natalka [10]2 years ago
5 0

The change in kinetic energy of the  system is 200 J

Kinetic energy is the energy that an object possesses as a result of its motion.

It is given by:

Kinetic energy = (1/2)m[v - u]²

Where m is the mass of the object, v is the final velocity and u is the initial velocity.

Given that m = 16 kg, v = 20 m/s, u = 25 m/s, hence:

Kinetic energy = (1/2) * 16 * (20 - 25)² = 200 J

The change in kinetic energy of the  system is 200 J

Find out more at: brainly.com/question/12669551

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Look at the question in the picture pls I need help
Lena [83]

Step-by-step explanation:

Let the painting's width be w inches and length be l inches.

w + 6 = 2l

w = 2l - 6 --(1)

2w + 2l = 84 --(2)

sub (1) into (2):

2(2l - 6) + 2l = 84

2l - 6 + l = 42

3l = 48

l = 16

when l = 16, w = 2(16) - 6 = 26

area of painting = lw = 16 x 26 = 416square inches

Therefore, only statements 1, 3 and 5 are true

Topic: Algebraic equations + Simultaneous linear equations

If you would like to venture further into mathematics, you can check out my Instagram page (learntionary) where I post notes and mathematics tips. Thanks!

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3 years ago
The x-intercept of the line whose equation is 2x - 3y= 6 is
QveST [7]
The x-intercept is 3 and the y-intercept is -2
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3 years ago
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Find sin x/2, cos x/2, and tan x/2 from the given information.. cos x = −15/17, 180° < x < 270°. . sin x/2=. . cos x/2=. .
sukhopar [10]
So base on your question the possible answer to that kind of question and the solution are the following and i hope you will understand the formula and free to ask some questions if needed.

<span>2<span>cos2</span><span>x2</span>=1+cosx=1−<span>1517</span>=<span>217</span>,<span>cos2</span><span>x2</span>=<span>117</span></span> <span>cos<span>x2</span>=−<span>1<span>17<span>−−</span>√</span></span>....(1)</span> <span>sin<span>x2</span>=<span>1<span>17<span>−−</span>√</span></span>,90<<span>x2</span><135</span> <span>sin<span>x2</span>>0,cos<span>x2</span><0,tan<span>x2</span><0</span> <span>2<span>sin2</span><span>x2</span>=1−cosx=1−<span><span>−15</span>17</span>=<span>3217</span>,sin<span>x2</span>=<span>4<span>17<span>−−</span>√</span></span>.....(2)</span><span> divide (2) by (1) and get the value of tan x/2</span>
6 0
2 years ago
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78% of 68 is what number?
raketka [301]

Answer:

53.04

Step-by-step explanation:

7 0
3 years ago
Y is a random variable that is distributed N(-16, 1.21). Find k such that Prob(-15.043 &lt; Y ≤ k) = 0.1546. (Round your answer
IgorLugansk [536]

Transform <em>Y</em> to <em>Z</em>, which is distributed N(0, 1), using the formula

<em>Y</em> = <em>µ</em> + <em>σZ</em>

where <em>µ</em> = -16 and <em>σ</em> = 1.21.

Pr[-15.043 < <em>Y</em> ≤ <em>k</em>] = 0.1546

Pr[(-15.043 + 16)/1.21 < (<em>Y</em> + 16)/1.21 ≤ (<em>k</em> + 16)/1.21] = 0.1546

Pr[0.791 < <em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] - Pr[<em>Z</em> < 0.791] = 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] = 0.1546 + Pr[<em>Z</em> < 0.791]

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546 + 0.786

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.940

Take the inverse CDF of both sides (<em>Φ(x)</em> denotes the CDF itself):

(<em>k</em> + 16)/1.21 ≈ <em>Φ⁻¹</em> (0.940) ≈ 1.556

Solve for <em>k</em> :

<em>k</em> + 16 = 1.21 • 1.556

<em>k</em> ≈ -14.118

8 0
3 years ago
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