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AfilCa [17]
3 years ago
14

The famous arcade game Space Invaders was first adapted to which home console?

Computers and Technology
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

Attari VCS 2600

Explanation:

It was in 1980 and then home gaming really took off!

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If you have glasses the liquid and cloth can be used to clean it. You spray the camera, then use the cloth to wipe it up. If you don't have them the dollar store should have some, or even places like Walmart and Maceys.
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3 years ago
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What color is excel?​
Eduardwww [97]

Answer:

green

Explanation:

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_____________is the act of protecting information and the systems that store and process it.A.Information systems securityB.Poli
mylen [45]

Answer:

A. Information System Security (ISS)

Explanation:

Information System security is a very important security in any organization.

The main focus of Information system security is the system itself and the information that the system possesses, processes and stores.

Information system security, or infosec for short, is the modality involved in protecting information and in making it available.

With Infosec,

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2. the data an organization uses is protected ensuring integrity

3. programs, applications and technology implemented on an organization's systems are safely used.

Hope this helps!

3 0
3 years ago
Read 2 more answers
Write a class called MagicSquare, which contains a single method called check that accepts a two-dimensional array as an argumen
ira [324]

Answer:

public class MagicSquare {

   public static void main(String[] args) {

       int[][] square = {

               { 8, 11, 14, 1},

               {13, 2, 7,12},

               { 3, 16, 9, 6},

               {10, 5, 4, 15}

       };

       System.out.printf("The square %s a magic square. %n",

               (isMagicSquare(square) ? "is" : "is not"));

   }

   public static boolean isMagicSquare(int[][] square) {

       if(square.length != square[0].length) {

           return false;

       }

       int sum = 0;

       for(int i = 0; i < square[0].length; ++i) {

           sum += square[0][i];

       }

       int d1 = 0, d2 = 0;

       for(int i = 0; i < square.length; ++i) {

           int row_sum = 0;

           int col_sum = 0;

           for(int j = 0; j < square[0].length; ++j) {

               if(i == j) {

                   d1 += square[i][j];

               }

               if(j == square.length-i-1) {

                   d2 += square[i][j];

               }

               row_sum += square[i][j];

               col_sum += square[j][i];

           }

           if(row_sum != sum || col_sum != sum) {

               return false;

           }

       }

       return d1 == sum && d2 == sum;

   }

}

5 0
3 years ago
Write an application that prompts a user for two integers and displays every integer between them. Display There are no integers
olga2289 [7]

Answer:

x = int(input("Enter an integer: "))

y = int(input("Enter another integer: "))

if x > y:

   for number in range(y+1, x):

       print(number, end=" ")

elif y > x:

   for number in range(x+1, y):

       print(number, end=" ")

else:

   print("There are no integers between {} and {}".format(x, y))

Explanation:

*The code is in Python.

Ask the user to enter the two integers, x and y

Since we want our program to run regardless of which entered value is larger, we need to compare the numbers to be able to create the loop that prints the numbers.

Check if x is greater than y. If it is, create a for loop that iterates from y+1 to x-1 and print the numbers

Otherwise, check if y is greater than x. If it is, create a for loop that iterates from x+1 to y-1 and print the numbers

If none of the previous part is executed, print that there are no integers between

4 0
3 years ago
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