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Schach [20]
3 years ago
11

Two technicians are discussing the voltage measurements taken on the circuit below: V1 = 12Volts; V2 = 12Volts; V3 = 0Volts; V4

= 0Volts. Technician A states that these measurements could be caused by an open in the switch. Technician B states that these measurements indicate normal operation. Which technician is correct?
Computers and Technology
1 answer:
Gennadij [26K]3 years ago
6 0
Technician A is correct
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Many major employers routinely monitor the performance of their employees through the computers and telephones they use. Employe
STALIN [3.7K]

Answer:

Employers are allowed to check the number of keystrokes that word processors enter during the day.

Explanation:

An employer is authorized to monitor the activity of its employee when:

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3 years ago
If your computer is frozen what is something you would do to troubleshoot the problem ​
SpyIntel [72]

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4 0
1 year ago
Package Newton’s method for approximating square roots (Case Study 3.6) in a function named newton. This function expects the in
notka56 [123]

Answer:

import math

#Initialize tolerance

tolerance = 0.000001

def newton(x):

   """ Returns the square root of x """

   #Performs the successive approximations

   estimate = 1.0

   while True:

       estimate = (estimate + x / estimate) / 2

       difference = abs(x - estimate ** 2)

       if difference <= tolerance:     # Break out of loop if difference is less than tolerance

           break            

       return estimate     # While the difference value is > TOLERANCE, the process continues

def main():

   """Allows the user to obtain square roots."""

   while True:

       #Receive the input number from the user

       x = input("Enter a positive number or enter/return to quit: ")

       if x == "":     #if user presses "Enter" then exit the program

           break       # Otherwise, continue the process of allowing new numbers

       x = float(x)

       #Output the result

       print("The programs estimate of the square root of ", x, "is ", round(newton(x),2))

       print("Python's estimate: ", math.sqrt(x))

main()

8 0
2 years ago
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