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Yuki888 [10]
3 years ago
14

convert the following c code to mips. assume the address of base array is associated with $s0, n is associated with $s1, positio

n is associated with $t0, c is associated with $t1, d is associated with $t2, and swap is associated with $t3 for (c
Computers and Technology
1 answer:
Brums [2.3K]3 years ago
7 0

Answer:

Explanation:

hello we will follow a step by step process for this code, i hope you find it easy.

Mips Equivalent code:

  sw      $0,0($fp)

.L7:

       lw      $2,12($fp)

       addiu   $2,$2,-1

       lw      $3,0($fp)

       slt     $2,$3,$2

       beq     $2,$0,.L2

       nop

       lw      $2,0($fp)

       sw      $2,8($fp)

       lw      $2,0($fp)

       addiu   $2,$2,1

       sw      $2,4($fp)

.L5:

       lw      $3,4($fp)

       lw      $2,12($fp)

       slt     $2,$3,$2

       beq     $2,$0,.L3

       nop

       lw      $2,8($fp)

       dsll    $2,$2,2

       daddu   $2,$fp,$2

       lw      $3,24($2)

       lw      $2,4($fp)

       dsll    $2,$2,2

       daddu   $2,$fp,$2

       lw      $2,24($2)

       slt     $2,$2,$3

       beq     $2,$0,.L4

       nop

       lw      $2,4($fp)

       sw      $2,8($fp)

.L4:

       lw      $2,4($fp)

       addiu   $2,$2,1

       sw      $2,4($fp)

       b       .L5

       nop

.L3:

       lw      $3,8($fp)

       lw      $2,0($fp)

       beq     $3,$2,.L6

       nop

       lw      $2,0($fp)

       dsll    $2,$2,2

       daddu   $2,$fp,$2

       lw      $2,24($2)

       sw      $2,16($fp)

       lw      $2,8($fp)

       dsll    $2,$2,2

       daddu   $2,$fp,$2

       lw      $3,24($2)

       lw      $2,0($fp)

       dsll    $2,$2,2

       daddu   $2,$fp,$2

       sw      $3,24($2)

       lw      $2,8($fp)

       dsll    $2,$2,2

       daddu   $2,$fp,$2

       lw      $3,16($fp)

       sw      $3,24($2)

.L6:

    lw      $2,0($fp)

       addiu   $2,$2,1

       sw      $2,0($fp)

       b       .L7

        nop

cheers  i hope this helps

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The program to this question as follows:

Program:

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Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

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String s1 = new String("Objected oriented programming language!");

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System.out.print(s2.charAt(i));

System.out.println();

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System.out.println("They are equal");

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String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

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} // end main

} // end class StringLab9

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