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Tems11 [23]
3 years ago
11

Please help answer all please

Mathematics
1 answer:
Amanda [17]3 years ago
4 0

Answer:????

Step-by-step explanation:

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Simplify by combining like terms: 3x + 2 + x + 7
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4x +9

3x and x are like terms
And 2 and 7 are like terms

Hope this helps :D
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HELPPPPP MEEEEE!!! #7
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Angle 6 and Angle 7 are each 90° since they’re on a straight line and are both equal.
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Angle 7 and Angle 1 are alternate exterior angles so that makes them congruent by definition.
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Every terminating decimal is a rational number True or False ?
wel

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True

Step-by-step explanation:

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Write the equation of a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2(sqrt5)
Xelga [282]

Answer:

\frac{x^2}{16}-\frac{b^2}{4}=1

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that  a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{4^2}{a^2}-\frac{0}{b^2} =1\\\frac{4^2}{a^2}=1\\ a^2=16\\a=\sqrt{16}=4\\ a=4

The foci c is at +/-2√5, using c² = a² + b²:

c^2=a^2+b^2\\(2\sqrt{5} )^2=4^2+b^2\\20 = 16 + b^2\\b^2=20-16\\b^2=4\\b=\sqrt{4}=2\\ b=2

Substituting the value of a and b to get the equation of the hyperbola:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\\\frac{x^2}{16}-\frac{b^2}{4}=1

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3 years ago
What is the value of the express?
spin [16.1K]

Answer:

wheres the expression

Step-by-step explanation:

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3 years ago
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