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DochEvi [55]
3 years ago
6

What is the length of line BC , rounded to the nearest tenth?

Mathematics
1 answer:
GuDViN [60]3 years ago
6 0
Hi I Think The Answer is:

31.2 units


Hope This Helped

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PLEASE HELP URGENT!!! 30 POINTS TO WHOEVER ANSWERS BOTH QUESTIONS!!
Alex Ar [27]
This isn’t 30 points this is 15
3 0
3 years ago
Find the perimeter of a rectangle if one side is 3x and the other side is 6x.
dexar [7]

Answer:

18x

Step-by-step explanation:

2(3x+6x)

6 0
3 years ago
a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
Tresset [83]

Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

Where

Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

8 0
3 years ago
A pair of in-line skates is on sale for $90 if this price represents a 9% discount on the original price what is the original pe
UkoKoshka [18]
1 + 0.09 = 1.09

90 * 1.09 = 98.1

The original price of the in-line skates was $98.1
5 0
3 years ago
Read 2 more answers
Find the center and radius of the circle (x+3)^2+(y-1)^2=81
sasho [114]

The equation of a circle is written as ( x-h)^2 + (y-k)^2 = r^2

h and k is the center point of the circle and r is the radius.

In the given equation (x+3)^2 + (y-1)^2 = 81

h = -3

k = 1

r^2 = 81

Take the square root of both sides:

r = 9

The center is (-3,1) and the radius is 9

5 0
3 years ago
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