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2 years ago

Given the whole number 3,257,098, in what place value is the 2

Mathematics

1 answer:

algol132 years ago

6 0

Answer: The hundred-thousandth place

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It is your first semester at college and you take out a $5000 loan and in order to pay off that loan by the end of the semester

kakasveta [241]

Answer:

5000-1250x

Step-by-step explanation:

All you need to do is find the amount of money you get paid a month and use variable x to represent the months and then subtract that from the money you need to pay off.

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3 years ago

3•x2 + 1(2)<br> (2)x-2(3)

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I got 4x if that isn’t right I will check again

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2 years ago

Express a^6n/a^3n with positive exponents

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I hope this helps you

a^6n-3n

a^3n

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3 years ago

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All numbers less than or equal to 22

alekssr [168]

Answer:

x ≤ 22

Step-by-step explanation:

≤ means less than or equal to

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3 years ago

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Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

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3 years ago