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jonny [76]
2 years ago
6

nts/viewer/classes/289ef1a5d7c341c284010 Select the compound inequality shown on the graph. 5 4 3 2 1 0 1 2 를 4​

Computers and Technology
1 answer:
Nezavi [6.7K]2 years ago
6 0
168 > 892 I just took the test
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Chunking is a good strategy for completing large assignments because it makes the work
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Answer:

ExChunking is a good strategy for completing large assignments because it makes the work

less boring.

more thorough.

less difficult.

more manageable.planation:

Explanation: less difficult (C)

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Write the function greeting that takes a string as input. That string will be formatted as Name Age Hobby, without any punctuati
Dmitriy789 [7]

Answer:

The function in Python is as follows:

def greetings(details):

   details = details.split(' ')

   print('Hello, '+details[0]+'!, I also enjoy '+details[2])

Explanation:

This defines the function

def greetings(details):

This splits the input string by space

   details = details.split(' ')

This prints the required output

   print('Hello, '+details[0]+'!, I also enjoy '+details[2])

After splitting, the string at index 0 represents the name while the string at index 2 represents the hobby

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What would a good digital citizen do in the following situation? Nick sees that his classmate left her email account open on a s
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3 years ago
Write a function that checks whether two words are anagrams. Two words are anagrams if they contain the same letters. For exampl
Masteriza [31]

Answer:

def isAnagram(s1, s2):

   list1=s1

   list2=s2

   sortedlist1 = sorted(list1)

   sortedlist2 = sorted(list2)

   if sortedlist1 == sortedlist2:

       print(list1+ " and "+list2+ " are anagram")

   else:

       print(list1+ " and "+list2+ " are not anagram")

Explanation:

Here is a call to the function isAnagram():

list1 =input("Enter String1 ")

list1 =input("Enter String2 ")

isAnagram(list1,list2)

Attached is the run and output for this program

4 0
3 years ago
A domestic air carrier airplane lands at an intermediate airport at 1815Z. The latest time it may depart without a specific auth
serious [3.7K]

Answer:

A domestic air carrier airplane lands at an intermediate airport at 1815Z. The latest time it may depart without a specific authorization from an aircraft dispatcher is <u>1915Z (1 hour)</u>.

Explanation:

Under the domestic operations, an airplane landed on intermediate airport can remain their for not more than one hour so the time would me 1 hour.

Here the time represented by 1815Z and 1915Z is in Zulu Time Zone as depicted from letter "Z". The first two digits represent the hour (0-24) and the next two represent the minutes (0-59).

  • Here the landing time is 6:15 pm while departing time is after one hour that is 7:15 pm (1915Z).

i hope it will help you.

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3 years ago
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