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jonny [76]
3 years ago
6

nts/viewer/classes/289ef1a5d7c341c284010 Select the compound inequality shown on the graph. 5 4 3 2 1 0 1 2 를 4​

Computers and Technology
1 answer:
Nezavi [6.7K]3 years ago
6 0
168 > 892 I just took the test
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B) cutting off part of the image

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Explain why the scenario below fails to meet the definition an assembly line.
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its not an assembly line

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What is a Layer 2 device that receives an electrical signal in one port, interprets the bits, and makes a filtering or forwardin
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Answer:

Router

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Router -

It is a networking device which helps to forward the data packets between the networks of the computer .

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4 years ago
Developers found a "time of check to time of use" (TOCTTOU) vulnerability in their application. The vulnerability made it possib
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This vulnerability above is taking advantage of the race condition process in the application.

<h3>What is race condition? </h3>

This race condition is said to be in the critical section or one that is a part of the program and it is a place where shared memory is accessed and it is concurrently worked on or executed by two or more threads.

Hence,  This vulnerability above is taking advantage of the race condition process in the application.

Learn more about race condition from

brainly.com/question/13445523

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2 years ago
Given five positive integers, find the minimum and maximum values that can be calculated by summing exactly four of the five int
Aloiza [94]

Using the knowledge in computational language in JAVA it is possible to write a code that  print the respective minimum and maximum values as a single line

<h3>Writting the code in JAVA:</h3>

<em>import java.io.*;</em>

<em>import java.util.*;</em>

<em>import java.text.*;</em>

<em>import java.math.*;</em>

<em>import java.util.regex.*;</em>

<em />

<em>public class Solution {</em>

<em>    public static void main(String[] args) {</em>

<em>        Scanner in = new Scanner(System.in);</em>

<em>        long sum = 0;</em>

<em>        long max = Long.MIN_VALUE;</em>

<em>        long min = Long.MAX_VALUE;</em>

<em>        for (int i = 0; i < 5; i++){</em>

<em>            long n = in.nextLong();</em>

<em>            sum += n;</em>

<em>            max = Math.max(max, n);</em>

<em>            min = Math.min(min, n);</em>

<em>        }</em>

<em>        System.out.println((sum - max) + " " + (sum - min));</em>

<em>    }</em>

<em>}</em>

See more about JAVA at brainly.com/question/12974523

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8 0
2 years ago
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