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2 years ago

Please someone answer ASAP!!

Mathematics

1 answer:

Nina [5.8K]2 years ago

8 0

Answer:

<h2> Please put some pictures so we can answer your question,so you will not mad or angry that we're answering this question.</h2>

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Pls help !!!!!!!!!!!!!!

garri49 [273]

The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For a quadratic function in standard form, y=ax2+bx+c , the axis of symmetry is a vertical line x=−b2a .

6 0

2 years ago

Find the length of the segment.<br><br> please help

maksim [4K]

Answer:

$\sqrt{29}$

Step-by-step explanation:

Use the distance formula!

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

If we plug in the coordinates:

$d=\sqrt{(3-(-2))^2+(4-2)^2} \\d=\sqrt{25+4}\\ d=\sqrt{29}$

That's our answer!

6 0

1 year ago

Read 2 more answers

Consider the circle of radius 5 centered at (0, 0). Find an equation of the line tangent to the circle at the point (3, 4) in sl

Wittaler [7]

Answer:

$\displaystyle y= -\frac{3}{4} x + \frac{25}{4}$ .

Step-by-step explanation:

The equation of a circle of radius $5$ centered at $(0,0)$ is:

$x^{2} + y^{2} = 5^{2}$ .

$x^{2} + y^{2} = 25$ .

Differentiate implicitly with respect to $x$ to find the slope of tangents to this circle.

$\displaystyle \frac{d}{dx}[x^{2} + y^{2}] = \frac{d}{dx}[25]$

$\displaystyle \frac{d}{dx}(x^{2}) + \frac{d}{dx}(y^{2}) = 0$ .

Apply the power rule and the chain rule. Treat $y$ as a function of $x$ , $f(x)$ .

$\displaystyle \frac{d}{dx}(x^{2}) + \frac{d}{dx}(f(x))^{2} = 0$ .

$\displaystyle \frac{d}{dx}(2x) + \frac{d}{dx}(2f(x)\cdot f^{\prime}(x)) = 0$ .

That is:

$\displaystyle \frac{d}{dx}(2x) + \frac{d}{dx}\left(2y \cdot \frac{dy}{dx}\right) = 0$ .

Solve this equation for $\displaystyle \frac{dy}{dx}$ :

$\displaystyle \frac{dy}{dx} = -\frac{x}{y}$ .

The slope of the tangent to this circle at point $(3, 4)$ will thus equal

$\displaystyle \frac{dy}{dx} = -\frac{3}{4}$ .

Apply the slope-point of a line in a cartesian plane:

$y - y_0 = m(x - x_0)$ , where

$m$ is the gradient of this line, and
$(x_0, y_0)$ are the coordinates of a point on that line.

For the tangent line in this question:

$\displaystyle m = -\frac{3}{4}$ ,
$(x_0, y_0) = (3, 4)$ .

The equation of this tangent line will thus be:

$\displaystyle y - 4 = -\frac{3}{4} (x - 3)$ .

That simplifies to

$\displaystyle y= -\frac{3}{4} x + \frac{25}{4}$ .

3 0

3 years ago

Look at the following graph of the given equation. Determine whether the equation is the function. Explain why or why not.

Drupady [299]

Answer:

Step-by-step explanation:

It is a function. Every x has only 1 y associated with it. You cannot find an exception to this rule.

Stated another more common way: if you take a ruler and lay it flat on the graph so that the ruler is parallel to the y axis, you will find the ruler will go through only one y for every x. That's called the vertical line test.

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3 years ago

Geometry sem 1 7.1.2 Exam: Semester 1 Exam

Alex777 [14]

Answer:

Step-by-step explanation:

6 0

2 years ago