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givi [52]
2 years ago
15

Plzzzzzzzzz help thank u

Mathematics
2 answers:
Vikki [24]2 years ago
6 0

Answer:

I think the answer is A

A is the answer

Readme [11.4K]2 years ago
4 0

Answer:

(b)

Step-by-step explanation:

you are taking 3 away from 1, leaving you with -2

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Which expression is equivalent to 11c-4c? A. 5c+2c B. 3c+7c
timurjin [86]
11c-4c = 7c
5c+2c= 7c
3c+7c= 10c

11c-4c= 5c+2c =A
4 0
3 years ago
Juno calculated the area of a square to be 4/9 square yard. Which shows the side length of the square?
Stella [2.4K]
\bf \textit{area of a square}\\\\
A=s^2~~
\begin{cases}
s=side's~length\\
--------\\
A=\frac{4}{9}
\end{cases}\implies \cfrac{4}{9}=s^2
\\\\\\
\sqrt{\cfrac{4}{9}}=s\implies \cfrac{\sqrt{4}}{\sqrt{9}}=s\implies \cfrac{2}{3}=s
3 0
3 years ago
In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any
Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

E \cap F = \emptyset,\quad E \cup F = \Omega

where \Omega is the whole sample space.

This implies that

P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day d_1.

The second footballer can be born on any other day, so he has 364 possible birthdays:

d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}

the probability for the first two footballers to be born on two different days is thus

1 \cdot \dfrac{364}{365} = \dfrac{364}{365}

Similarly, the third footballer can be born on any day, except d_1 and d_2:

d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}

so, the probability for the first three footballers to be born on three different days is

1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

So, the probability that at least two footballers are born on the same day is

1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

since the two events are complementary.

8 0
3 years ago
(CORRECT ANSWER GETS BRAINLIEST) Drag each object to show whether distance is proportional to time in the situation represented.
natka813 [3]

Answer:

a horse running around a race track and

a person running down a field to score a touchdown

DONT HAVE ENOUGH INFORMATION

the two graphs are proportional to time and

a dog jumping at a constant speed for 20min and

a truck passing through 4 cities at a constant speed are not proportional to time because they are constant

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is 10 more than 45,301
Aliun [14]

Answer:45,311

45,301+10=45,311

I hope this is good enough:

7 0
2 years ago
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