Answer:
Find the prime factors of each term in order to find the greatest common factor (GCF).
9a2b2
Answer:
9 23/40 kg
Step-by-step explanation:
The three bags ordered weighed a total of
... 3 × 4 2/5 = 12 6/5 = 13 1/5 . . . kg
The amount remaining at the end of the month was
... 2 3/4 + 7/8 = 2 6/8 + 7/8 = 2 13/8 = 3 5/8 . . . kg
The difference is the amount used.
... 13 1/5 - 3 5/8 = (13 -3) + (1/5 -5/8) = 10 + (1*8 -5*5)/(5*8)
... = 10 - 17/40
... = 9 23/40 . . . kg
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The sum or difference of fractions can always be computed from ...
... a/b ± c/d = (ad ± bc)/(bd)
In this case, bd = 5·8 = 40 is the least common denominator.
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A calculator will often handle problems like this very nicely.
Answer:
.121
Step-by-step explanation:
Divide 121 by 1000
Chris is twice as old as Bradley: C = 2B
Devin is eight years older than Bradley: D = B + 8
Mitchell is eight years older than Devin: M = B + 8 + 8
Bradley: B = B
Plug in the values:
-->
Subtract 24 from both sides.
5B = 104 - 24
5B = 80
B =
B = 16
Plug in the values to know the age of each player:
Chris: 2(16) Chris is 32 years old.
Devin: (16) + 8 Devin is 24 years old.
Mitchell: (16) + 8 + 8 Mitchell is 32 years old.
Bradley is sixteen years old.
To check your work, add up all of their ages: 2(32) + 24 + 16 = 104
Hope this was helpful.