Yes, they both are 2/7
Proof: Left-hand side
Simplify the following:
12/42
The gcd of 12 and 42 is 6, so 12/42 = (6×2)/(6×7) = 6/6×2/7 = 2/7:
Answer: 2/7
Right-hand side:
Simplify the following:
10/35
The gcd of 10 and 35 is 5, so 10/35 = (5×2)/(5×7) = 5/5×2/7 = 2/7:
Answer: 2/7
Given:
The line passing through (-2,5) and (2,p) has a gradient of
.
To find:
The value of p.
Solution:
If a line passes through two points, then the slope of the line is:
![m=\dfrac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
The line passing through (-2,5) and (2,p). So, the slope of the line is:
![m=\dfrac{p-5}{2-(-2)}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7Bp-5%7D%7B2-%28-2%29%7D)
![m=\dfrac{p-5}{2+2}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7Bp-5%7D%7B2%2B2%7D)
![m=\dfrac{p-5}{4}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7Bp-5%7D%7B4%7D)
It is given that the gradient or slope of the line is
.
![\dfrac{p-5}{4}=-\dfrac{1}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bp-5%7D%7B4%7D%3D-%5Cdfrac%7B1%7D%7B2%7D)
On cross multiplication, we get
![2(p-5)=-4(1)](https://tex.z-dn.net/?f=2%28p-5%29%3D-4%281%29)
![2p-10=-4](https://tex.z-dn.net/?f=2p-10%3D-4)
![2p=-4+10](https://tex.z-dn.net/?f=2p%3D-4%2B10)
![2p=6](https://tex.z-dn.net/?f=2p%3D6)
Divide both sides by 2.
![p=3](https://tex.z-dn.net/?f=p%3D3)
Therefore, the value of p is 3.
<h3>
Answer: addition property of inequality</h3>
================================================
Explanation:
These are the steps to focus on
step 3: -6x - 8 < -2
step 4: -6x < 6
The move from the third step to the fourth step has us adding 8 to both sides. Therefore, we use the addition property of inequality.
That property has four forms
- If
then ![a + c > b+c](https://tex.z-dn.net/?f=a%20%2B%20c%20%3E%20b%2Bc)
- If
then ![a+c < b+c](https://tex.z-dn.net/?f=a%2Bc%20%3C%20b%2Bc)
- If
then ![a + c \ge b+c](https://tex.z-dn.net/?f=a%20%2B%20c%20%5Cge%20b%2Bc)
- If
then ![a+c \le b+c](https://tex.z-dn.net/?f=a%2Bc%20%5Cle%20b%2Bc)
It's similar to the idea of starting with a = b, then adding c to both sides to get a+c = b+c
We add the same thing to both sides to keep things balanced.
Using an exponential function, it is found that the Tequesta settlement is 1845 years old.
<h3>What is an exponential function?</h3>
The exponential equation for a decaying amount of a substance is given by:
![A(t) = A(0)e^{-rt}](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29e%5E%7B-rt%7D)
In which:
- A(0) is the initial value.
- r is the decay rate, as a decimal.
Researching on the internet, the half-life of carbon 14 is of 5,730 years, hence A(5730) = 0.5A(0), which we use to find r.
![A(t) = A(0)e^{-rt}](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29e%5E%7B-rt%7D)
![0.5A(0) = A(0)e^{-5730r}](https://tex.z-dn.net/?f=0.5A%280%29%20%3D%20A%280%29e%5E%7B-5730r%7D)
![e^{-5730r} = 0.5](https://tex.z-dn.net/?f=e%5E%7B-5730r%7D%20%3D%200.5)
![\ln{e^{-5730r}} = \ln{0.5}](https://tex.z-dn.net/?f=%5Cln%7Be%5E%7B-5730r%7D%7D%20%3D%20%5Cln%7B0.5%7D)
![5730r = -\ln{0.5}](https://tex.z-dn.net/?f=5730r%20%3D%20-%5Cln%7B0.5%7D)
![r = -\frac{\ln{0.5}}{5730}](https://tex.z-dn.net/?f=r%20%3D%20-%5Cfrac%7B%5Cln%7B0.5%7D%7D%7B5730%7D)
![r = 0.00012096809](https://tex.z-dn.net/?f=r%20%3D%200.00012096809)
Hence, the equation is:
![A(t) = A(0)e^{-0.00012096809t}](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29e%5E%7B-0.00012096809t%7D)
The wood chips were found to contain 80% of the atmospheric carbon-14, hence we have to find t for which A(t) = 0.8A(0).
![A(t) = A(0)e^{-0.00012096809t}](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29e%5E%7B-0.00012096809t%7D)
![0.8A(0) = A(0)e^{-0.00012096809t}](https://tex.z-dn.net/?f=0.8A%280%29%20%3D%20A%280%29e%5E%7B-0.00012096809t%7D)
![e^{-0.00012096809t} = 0.8](https://tex.z-dn.net/?f=e%5E%7B-0.00012096809t%7D%20%3D%200.8)
![\ln{e^{-0.00012096809t}} = \ln{0.8}](https://tex.z-dn.net/?f=%5Cln%7Be%5E%7B-0.00012096809t%7D%7D%20%3D%20%5Cln%7B0.8%7D)
![-0.00012096809t = \ln{0.8}](https://tex.z-dn.net/?f=-0.00012096809t%20%3D%20%5Cln%7B0.8%7D)
![t = -\frac{\ln{0.8}}{0.00012096809}](https://tex.z-dn.net/?f=t%20%3D%20-%5Cfrac%7B%5Cln%7B0.8%7D%7D%7B0.00012096809%7D)
![t = 1845](https://tex.z-dn.net/?f=t%20%3D%201845)
The Tequesta settlement is 1845 years old.
You can learn more about exponential functions at brainly.com/question/25537936
Answer:
Option D
Step-by-step explanation:
We are given the following equations -
![\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D-5x-12y-43z%3D-136%5C%5C%20-4x-14y-52z%3D-146%5C%5C%2021x%2B72y%2B267z%3D756%5Cend%7Bbmatrix%7D)
It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -
First, I swapped the first and third rows.
Leading coefficient of row 2 canceled.
The start value of row 3 was canceled.
Matrix rows 2 and 3 were swapped.
Leading coefficient in row 3 was canceled.
![\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&0&0&\frac{4}{9}\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D21%2672%26267%26756%5C%5C%200%26%5Cfrac%7B36%7D%7B7%7D%26%5Cfrac%7B144%7D%7B7%7D%2644%5C%5C%200%260%260%26%5Cfrac%7B4%7D%7B9%7D%5Cend%7Bbmatrix%7D)
And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -
![\begin{bmatrix}1&0&-1&0\\ 0&1&4&0\\ 0&0&0&1\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D1%260%26-1%260%5C%5C%200%261%264%260%5C%5C%200%260%260%261%5Cend%7Bbmatrix%7D)
The positioning of the zeros indicated that there was no solution!
<u><em>Hope that helps!</em></u>