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shutvik [7]
2 years ago
10

How to solve quadratic inequalities.

Mathematics
1 answer:
Digiron [165]2 years ago
6 0

Find all the zeros of the polynomial, and arrange the zeros in increasing order. ...

Plot those numbers on the number line as open or closed points based upon the original inequality symbol.

Choose a test value in each interval to see if the interval satisfies the inequality or not.

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Find the exact value of cos 120° in simplest form with a rational<br> denominator.
IRINA_888 [86]

Given:

cos 120°

To find:

The exact value of cos 120° in simplest form with a rational  denominator.

Solution:

We have,

\cos 120^\circ

It can be written as

\cos 120^\circ=\cos (90^\circ+30^\circ)

\cos 120^\circ=-\sin 30^\circ             [\because \cos (90^\circ-\theta)=-\sin \theta]

\cos 120^\circ=-\left(\dfrac{1}{2}\right)             [\because \sin 30^\circ=\dfrac{1}{2}]

\cos 120^\circ=-\dfrac{1}{2}

Therefore, the exact value of cos 120° is -\dfrac{1}{2}.

7 0
3 years ago
Show work pls What is the equation in slope-intercept form of the line that passes through the point (2, -2) and is perpendicula
sergij07 [2.7K]

Answer:

Step-by-step explanation:

the slope-International cept frome y= mx + b was where m is the slope and b y-intercept

y=mx +b

m= -2/5

b=2

slope is :2/5

y-intercept is :2

x.   y  

0.  2

1    8/5

6 0
3 years ago
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Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).
balandron [24]
If it is bisector then it co ordinate points is in mid way(3,-2)

and it is perpendicular so its slope m2=-1/m1
where m1 is slope of another line passes through (4,1) nd (2,-5)

m1=-5-1/2-4=3
m2==-1/3

so equation of line is
y-3= -1/3(x+2)
4 0
3 years ago
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What are so sayings for pemdas?
bearhunter [10]

Answer:

Parenthesis

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Multiplication

Division

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Subtraction

8 0
3 years ago
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If the radius of the circle below is 12 feet, find the area of the shaded region.
aniked [119]

Answer:

465.61 ft

Step-by-step explanation:

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