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balu736 [363]
2 years ago
8

Solve the problem:

Mathematics
1 answer:
Over [174]2 years ago
4 0

Answer:

Step-by-step explanation:

ohfpifpijpijsfpjspijpsijfpsjfpsjfpisjfpijsfpsijf

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Maria types a 5 page paper in 40 minutes. At this rate, how many pages will she type in 136 minutes?
kvv77 [185]
In this equation, X = 17
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3 years ago
Noah tried to prove that cos(θ)=sin(θ) using the following diagram. His proof is not correct.
alukav5142 [94]

Answer:

The first statement is incorrect. They have to be complementary.

Step-by-step explanation:

You can't say the measure of angle B is congruent to theta because it is possible for angles in a right triangle to be different.

You can only say that what he said is true if the angle was 45 degrees, but based on the information provided it is not possible to figure that out.

The other two angles other than the right angle in a right triangle have to add up to 90 degrees, which is the definition of what it means for two angles to be complementary. A is the correct answer.

3 0
3 years ago
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Evaluate |-a^2|, given a = 5, b = -3, and c = -2.
geniusboy [140]
The sunset is 25. how this helps!
7 0
3 years ago
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AABC AEFG
Paraphin [41]

Answer:

la a

Step-by-step explanation:

espero que te sirva

6 0
3 years ago
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Given $m\geq 2$, denote by $b^{-1}$ the inverse of $b\pmod{m}$. That is, $b^{-1}$ is the residue for which $bb^{-1}\equiv 1\pmod
goblinko [34]

(2+3)^{-1}\equiv5^{-1}\pmod7 is the number <em>L</em> such that

5L\equiv1\pmod7

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so <em>L</em> = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

2a\equiv1\pmod7\implies a\equiv4\pmod7

since 2*4 = 8, whose residue is 1 mod 7;

3b\equiv1\pmod7\implies b\equiv5\pmod7

which we got for free by finding the inverse of 5 earlier. So

2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7

and so <em>R</em> = 2.

Then <em>L</em> - <em>R</em> = 1.

6 0
3 years ago
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