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3 years ago

What whole number best approximates the value of x? 100 102 103 104

Mathematics

2 answers:

Monica [59]3 years ago

5 0

I'm pretty sure your answer should be approximately 10.2 because if its asking what "x" is closest to, then 10.2 would be the number it is closest to on the number line. Hope this helps you ^-^

Katarina [22]3 years ago

3 0

Answer

104

Explanation

The √x from the number line is about 10.2.

Or say less than 10.2. The number is also much greater than 10.1.

If you square 10.2 to get the value of x;

10.2² = 104.04

So, the approximate value of x is 104.

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3) At a school several teachers were holding a contest to see which class could earn the most trivia points. Mrs. Clawson's clas

Snezhnost [94]

Answer:

Mean: 89

Median: 90

Mode: 94

Range: 12

5 0

3 years ago

You have 8 gallons of lemonade to sell. You use cone-shaped cups that are 9 centimeters in diameter and 12 centimeters tall. Eac

andre [41]

You will need 119 cups to sell all of the lemonade.

Step-by-step explanation:

Given,

Diameter of cups = 9 cm

Radius of cup = $\frac{Diameter}{2}=\frac{9}{2}=4.5\ cm$

Height of cups = 12 cm

We will find volume of cup.

$Volume = \frac{1}{3}\pi r^2h\\$

Putting all the values

$Volume=\frac{1}{3}(3.14)(4.5)^2(12)\\\\Volume=\frac{1}{3}(3.14)(20.25)(12)\\\\Volume= \frac{763.02}{3}\\\\Volume= 254.34\ cm^3$

Therefore;

Each cup can hold 254.34 cubed centimeter of lemonade.

Number of gallons = 8

1 gallon = 3785 cm³

8 gallons = 3785*8 = 30280 cm³

Let,

x = Number of cups

Volume of lemonade in one cup * Number of cups = Volume of 8 gallons

254.34x=30280

Dividing both sides by 254.34

$\frac{254.34x}{254.34}=\frac{30280}{254.34}\\x=119.05$

Rounding off to nearest whole number

x = 119

You will need 119 cups to sell all of the lemonade.

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4 0

3 years ago

Doug estimates that his soccer team will win 7 games this year. The team actually wins 10 games. What is the percent error of Do

baherus [9]

Answer: 30%

Step-by-step explanation:

Percent error = $\dfrac{|\text{Estimated value - Actual value}|}{\text{Actual value}}\times100\%$

Estimated number of games win this year = 7

Actual number of games won = 10

Now , the percent error of Doug’s estimate = $\dfrac{|7-10|}{10}\times100\%= \dfrac{3}{1}\times10\%=30\%$

Hence, the percent error of Doug’s estimate = 30%

6 0

3 years ago

Read 2 more answers

Find number a and k so that x-2 is afactor OF F(x)=x4-2ax tax- X+k and F(-1)=3

Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

$f(x)=x^4-2ax^3+ax^2- x+k$

and

$f(-1)=3$

Answer:

$k = -2$ and $a=1$

Step-by-step explanation:

Given

$f(x)=x^4-2ax^3+ax^2- x+k$

$Factor:\ x - 4$

$f(-1)=3$

Required

Find a and k

For $f(-1)=3$

Substitute -1 for x

$f(x)=x^4-2ax^3+ax^2- x+k$

$f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k$

$f(-1) = 1 - 2a *-1 + a*1 +1 + k$

$f(-1) = 1 +2a + a +1 + k$

$f(-1) = 2 +3a + k$

Substitute 3 for f(-1)

$3 = 2 +3a + k$

Collect Like Terms

$3 - 2 = 3a + k$

$1 = 3a + k$

Also:

If $x - 2$ is a factor, then

$f(2) = 0$

Substitute 2 for x and 0 for f(x)

$f(x)=x^4-2ax^3+ax^2- x+k$

$0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k$

$0 = 16 - 2a * 8 + a * 4 - 2 + k$

$0 = 16 - 16a + 4a - 2 + k$

$0 = 16 - 12a - 2 + k$

Collect Like Terms

$2 - 16 = - 12a + k$

$-14 = k - 12a$

$k = 12a - 14$

Substitute 12a - 14 for k in $1 = 3a + k$

$1 = 3a + 12a - 14$

$1 = 15a - 14$

Collect Like Terms

$15a = 1 + 14$

$15a = 15$

Solve for a

$a = \frac{15}{15}$

$a=1$

Substitute 1 for a in $k = 12a - 14$

$k = 12 * 1 - 14$

$k = 12 - 14$

$k = -2$

3 0

3 years ago

Solve the inequality. -1.5(4x+1) ≥ 45-25(x+1)

777dan777 [17]

Answer:

x ≥ 21.5/19

Step-by-step explanation:

-1.5(4x + 1) ≥ 45 - 25(x + 1)

-6x - 1.5 ≥ 45 - 25x - 25

-6x + 25x ≥ 45 - 25 + 1.5

19x ≥ 21.5

x ≥ 21.5/19

3 0

2 years ago