Answer:
B. There is one real, double root
Step-by-step explanation:
For ax² + bx + c = 0, the discriminant is b² − 4ac.
If the discriminant is positive and a perfect square, there are two real, rational roots.
If the discriminant is positive and not a perfect square, there are two real, irrational roots.
If the discriminant is 0, there is one real, double root.
If the discriminant is negative, there are two complex roots.
Here, a = 64, b = -16, and c = 1.
b² − 4ac
= (-16)² − 4(64)(1)
= 0
The discriminant is 0. Therefore, there is one real, double root
Answer:
Adam and buford
Step-by-step explanation:
Answer:
24:40, and 6:10
Step-by-step explanation:
I hope my answer was helpful and accurate! Have a blessed day!!
P.S may I please have brainliest if my answers deserves it, I don't normaly ask I currently have enought points but not enough brainliest to level up
<span>x^2 + 8x – 48 = 0
That is a quadratic equation where
a = 1
b = 8
c = -48
We can solve it by using the quadratic formula:
x = [-b +-sq root (b^2 - 4ac)] / 2a
x = [-8 +- sq root (64 -4*1*-48)] / 2*1
</span><span>x = [-8 +- sq root (256)] / 2
x = [-8 +-16] / 2
x1 = 8 / 2 = 4
x2 = -24 / 2 = -12
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