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m_a_m_a [10]
3 years ago
11

for a certain type of heater, the increase in gas bills is directly proportional to the temperature setting (in fahrenheit). if

the gas bills increased by $20 when the temperature setting is increased by 4 degrees fahrenheit, by how much will expenses increase when the temperature setting is increased by 10 degrees fahrenheit
Mathematics
1 answer:
erica [24]3 years ago
7 0

Answer:

The gas bill increases by $50

Step-by-step explanation:

We know that the increase in gas bills is directly proportional to the temperature setting. Let's take the increase in gas bills as g and increase in temperature setting as t. Thus, this can be written as:

g ∝ t

In every proportionality, there is a constant k, so it will be:

g = kt

It is mentioned that when the temperature setting increases by 4, the gas bill increases by $20, so in terms of the constant, we can write it as:

20 = k 4

We don't know the value of the constant, so we have to first find it out.

k = 20 ÷ 4

k = 5

Thus,

g = 5t

Now that we know the value of the constant, we can find by how much the gas bill will increase if the temperature setting increases by 10.

g = 5 × 10

g = <u>50</u>

∴ the gas bill increases by $50 when the temperature setting increases by 10 degrees Fahrenheit.

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Deffense [45]

Answer:

a

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b

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c

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.          

Step-by-step explanation:

From the question we are told we are told that  

   The  equation for the temperature of a cup of coffee place on a counter is

         H= f(t)

Here  t is the time in minutes the  coffee was put on the counter

Generally  f(t)'  is the derivative of  f(t) at it represents the change of the temperature of the cup of coffee with respect to time

 Generally for the coffee placed on the counter after a couple of minutes the temperature will decrease hence  f(t)' is  negative

Generally the unit of the temperature is in degrees Celsius while that of time is  in minutes

  So the change in temperature with time f(35)' will be in degrees Celsius/minutes (i.e  degC/min)

  From the question we are told that

        |f(35)'| =  1.5

i.e  the rate of change of temperature after 35 minutes is  1.5

and

         |f(35)| =  68

i.e the temperature of the cup of coffee after 35 minutes is  67 degC

Now after another   t=  30  seconds =  \frac{30}{60}= 0.5 \ minutes the  rate  of change of the temperature of the cup of  coffee is  

          R =  |f(35)'| *  t

=>        R = 1.5  *  0.5

=>        R = 0.75    

So

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.  

     

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