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Luba_88 [7]
3 years ago
8

Please tell me the answer to X. I really need your help. I'll even give you Brainliest if you give a proper answer with no downl

oad links. You should also give an explanation.

Mathematics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

6

Step-by-step explanation:

expand

x-7= 1/4x-10/4

3/4x=18/4

multiply 4 on both sides to get rid of the denominator

3x=18

x=6

check work by substituting

6-7= 1/4(6-10)

-1= 1/4(-4)

-1=-1

they are equal, so it's correct

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12 / 6

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Jessica wants to plan where she will place furniture in her room, so she has drawn a scale model of her room in order to begin p
Setler79 [48]
To solve this problem you must apply the proccedure shown below:
 1. You have that:
<span> - The scale model is 11 inches long and 8.5 inches wide.
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 2. Therefore, the actual size of the door is:
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5 0
3 years ago
What is the slope of the line represented​
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6 0
3 years ago
If at least one of these two numbers is divisible by 6, then the product of these two numbers is divisible by 6. Neither of thes
lubasha [3.4K]

Answer:

(a)then the product of these two numbers is divisible by 6.

Step-by-step explanation:

If a and b are two integers where at least one of a or b is divisible by 6, the product ab will also be divisible by 6.

If, a is divisible by 6, a/6 = c (an integer).

Product of a and b, (ab)/6 = (a/6) X b =cb.

Likewise if b is divisible by 6, same rule applies.

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4 0
2 years ago
The quadratic function g(x) = a.ca + bx+c has the
Mumz [18]

<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

f(x)=ax^2+bx+c

Here we know that the leading coefficient a=1 so we reduce our equation to:

g(x)=x^2+bx+c

The roots are those values at which g(x)=0

So:

x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\  49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\

Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\  49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0

So we have:

(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}

Finding c from (1):

33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

5 0
3 years ago
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