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Luba_88 [7]
3 years ago
8

Please tell me the answer to X. I really need your help. I'll even give you Brainliest if you give a proper answer with no downl

oad links. You should also give an explanation.

Mathematics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

6

Step-by-step explanation:

expand

x-7= 1/4x-10/4

3/4x=18/4

multiply 4 on both sides to get rid of the denominator

3x=18

x=6

check work by substituting

6-7= 1/4(6-10)

-1= 1/4(-4)

-1=-1

they are equal, so it's correct

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Hey Guys Please???<br> I have a booklet to do and im failing my quiz<br> Thank so muchhhh
OlgaM077 [116]

Answer:

$47.92

Step-by-step explanation:

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6 0
2 years ago
Simplify the problem given.
maks197457 [2]
Step Number 1. is to Simplify \frac{4}{8}  to  \frac{1}{2}

Step Number 2. <span>Simplify so you get </span>\frac{x}{4} +  \frac{5}{3}

Done! :)
4 0
3 years ago
5. Arianna purchased a house for $156,000 and obtained a mortgage for $147,700. She purchased 2 discount points and 3 originatio
yan [13]
D i think is the answer
8 0
3 years ago
Read 2 more answers
a jar contains nickels and pennies. there are 56 coins in the jar in all. the total value of the coins is 1.52. how many pennies
nevsk [136]
1 penny is just 1c
one nickel is 5 pennies or 5c

alrite...

p = amount of pennies in the jar
n = amount of nickels in the jar

we know there are 56 coins in the jar, thus whatever "p" and "n" are,

p + n = 56

we also know, the total value of all pennies and nickels is one buck and 52 cents, or 1.52.. that's 152 pennies.

now, we know there are 5 pennies in one nickel, so in "n" nickels, there are 5*n pennies, or 5n, thus

p + 5n = 152

\bf \begin{cases}&#10;p+n=56\implies \boxed{n}=56-p\\&#10;p+5n=152\\&#10;----------\\&#10;p+5\left( \boxed{56-p} \right)=152&#10;\end{cases}

solve for "p", to see how many penny coins are there.

what about the nickels? well, n = 56 - p.
5 0
3 years ago
Sarah has some grapes. She gathers 3 more grapes. She now has 40 grapes.
marysya [2.9K]
Sarah had 37 grapes to begin with

40-3=37
3 0
2 years ago
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