
Factor each of the following differences of two squares and write your answer together with solution.

<h3><u>1. x² - 36</u></h3>

Rewrite
. The difference of squares can be factored using the rule:
.

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<h3><u>2. 49 - x²</u></h3>

Rewrite 49-x² as 7²-x². The difference of squares can be factored using the rule:
.

Reorder the terms.

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<h3><u>3. 81 - c²</u></h3>

Rewrite 81-c²as 9²-c². The difference of squares can be factored using the rule:
.

Reorder the terms.

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<h3><u>4</u><u>.</u><u> </u><u>m²</u><u>n</u><u>²</u><u> </u><u>-</u><u> </u><u>1</u></h3>

Rewrite m²n² - 1 as
. The difference of squares can be factored using the rule:
.

Check the picture below.
notice that the triangle ADH, since the segment AL is an angle bisector, meaning it cuts the angle A in two equal halves, then the triangle ADH is only using half of A.
The answer is SSA, that what I found
Without any calculations it's evident it can't be neither B (both numbers are even, so they're divisible by 2) nor C (the numbers end in 0 and 5, so they're divisible by 5).
A.

Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.

Indeed, those two numbers are relatively prime.
Answer:
For the first one ASA
Second SAS
Third SSS
Sorry if i am wrong
Step-by-step explanation: