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marissa [1.9K]
3 years ago
15

Which law states that energy cannot be created or destroyed, but can change from one form to another?

Chemistry
2 answers:
Hunter-Best [27]3 years ago
7 0

Answer:

the law of conservation of energy

Assoli18 [71]3 years ago
7 0

Answer:

a

Explanation:

edge 2021

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The work function is the energy that must be supplied to cause the release of an electron from a photoelectric material. The cor
vladimir2022 [97]

Answer:

No photoelectric effect is observed for Mercury.

Explanation:

From E= hf

h= Plank's constant

f= frequency of incident light

Threshold Frequency of mercury= 435×10^3/ 6.6×10^-34 × 6.02×10^23

f= 11×10^14 Hz

The highest frequency of visible light is 7.5×10^14. This is clearly less than the threshold frequency of mercury hence no electron is emitted from the mercury surface

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Formula for water what does the lack of a subscript after those O indicate
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It indicates that there is only one oxygen molecule
3 0
3 years ago
ure to answer all parts. The vapor pressure of ethanol (C2H5OH) at 20°C is 44 mmHg, and the vapor pressure of methanol (CH3OH) a
eimsori [14]

Answer:

P_{met}=40.98mmHg\\\\P_{et}=24.82mmHg

Explanation:

Hello

In this case, by considering the Raoult's law we can write:

P_{met}=x_{met}P_{sat,met}\\\\P_{et}=x_{et}P_{sat,et}

Whereas the purpose is to compute the pressures of both methanol and ethanol (pressures above the solution), thus, the first step is to compute the molar fractions:

n_{met}=25.3gCH_3OH*\frac{1molCH_3OH}{32gCH_3OH}=0.791molCH_3OH\\ \\n_{et}=47.1gCH_3CH_2OH*\frac{1molCH_3CH_2OH}{46gCH_3CH_2OH}=1.02molCH_3CH_2OH\\\\x_{met}=\frac{0.791mol}{0.791mol+1.02mol}=0.436\\ \\x_{et}=1-x_{met}=1-0.436=0.564

Therefore, the pressures turns out:

P_{met}=0.436*94mmHg=40.98mmHg\\\\P_{et}=0.564*44mmHg=24.82mmHg

Best regards.

8 0
3 years ago
How much does one mole of NH3 weigh?
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17.031 g/mol Hope this helps you
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What happens when you break earphones into smaller pieces
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Answer:

Well its not gonna work anymore and you will be able to all the wires in the earphones!

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