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ehidna [41]
2 years ago
8

Which area is most likely to support a marsh ecosystem?.

Chemistry
1 answer:
andriy [413]2 years ago
5 0

Answer:

A location that is humid, would most likely support a marsh ecosystem.

Explanation:

The Florida Everglades are an example of a marsh :)

"Marshes are a type of wetland ecosystem where water covers the ground for long periods of time. Marshes are dominated by herbaceous plants, such as grasses, reeds, and sedges."

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Calculate the ΔHrxn for the following
Vesnalui [34]

Answer:

2 NO (g) → N2 (g) + O2 (g)

2 NOCl (g) → 2 NO (g) + Cl2 (g)

____________________________

2NOCl (g) ⟶ N2 (g) + O2 (g) + Cl2 (g)

ΔH = [90.3 kJ x 2 x -1] +  [-38.6 kJ x -1 x 2] = -103.4 kJ

The ΔH for the reaction is -103.4 kJ

6 0
3 years ago
Tungsten fits best into which category?
nordsb [41]

Answer:

B. Element

Explanation:

Tungsten is an chemical element

4 0
2 years ago
Read 2 more answers
Hydrogen peroxide decomposes to form water and oxygen gas
EleoNora [17]
True? If that’s what you are asking. It does decompose to that.
7 0
3 years ago
A solution of copper sulfate (CuSO4) produced by bioleaching has a concentration of 0.319 g/dm3 Relative atomic masses (Ar): Cu
Tanya [424]

moles Cu produced : 0.002

<h3>Further explanation</h3>

Concentration of copper sulfate (CuSO₄) : 0.319 g/dm³

MW CuSO₄ :

\tt =63.5+32+4\times 16=159.5~g/mol

mol CuSO₄ /dm³ :

\tt \dfrac{0.319}{159.5}=0.002

CuSO₄⇒Cu²⁺ + SO₄²⁻

mol Cu : mol CuSO₄ = 1 : 1 , so mol Cu²⁺=0.002

6 0
3 years ago
The molar mass of hydrogen molecules is 2g/mol and the molar mass of oxygen molecules is 32g/mol. What is the ratio of the avera
Alona [7]

Answer:

1

Explanation:

For an ideal gas, the average kinetic energy is given by:

Ek = (3/2)*n*R*T

Where n is the number of moles, R is the gas constant (8.31 J/mol*K), and T the temperature. The gases have the same number of moles, and the same temperature, so they will have the same average kinetic energy:

Ek = (3/2)*1*8.31*300

Ek =3739.5 J

So, the ratio between then is 1.

8 0
3 years ago
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