1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
icang [17]
3 years ago
8

Which of the following is equal to

Mathematics
1 answer:
Tanzania [10]3 years ago
8 0

Answer:  2x^3-2x^2-13x+3

======================================================

Work Shown:

I'm assuming you meant to say (x - 3)(2x^2 + 4x - 1)

Let y = x-3

So,

(x - 3)(2x^2 + 4x - 1)\\\\y(2x^2 + 4x - 1)\\\\y2x^2 + y4x - y\\\\2x^2(y) + 4x(y) - (y)\\\\2x^2(x-3) + 4x(x-3) - (x-3)\\\\2x^3-6x^2 + 4x^2-12x - x+3\\\\2x^3-2x^2-13x+3\\\\

The basic idea is to use the distribution rule (line 3 and line 6) and then combine like terms.

You might be interested in
need helpA triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(
iogann1982 [59]

Answer:

2.5

Step-by-step explanation:

The dilation is 2.5. Using the point b(0,4) and B' (0,10), divide 10/4 you get 2.5.

7 0
3 years ago
Solve the system of equations.
Leno4ka [110]
I don’t know sorry thanks for the points
3 0
3 years ago
A sporting goods store sells triangular team pennants in two sizes. The base of one pennant is 18 in. and the length of the side
juin [17]
This is a proportion problem because the problem stated that the two team pennants are similar.

Pennant 1 = base = 18 in ; length = 9 inches
Pennant 2 = base =   6 in ; length = x ?

9/18 = x/6
9*6 = 18x
54 = 18x
54/18 = x
3 = x

The length of the  side of the smaller pennant is 3 inches.
6 0
4 years ago
Read 2 more answers
Marcus was training for a 2,000 meter race. He had to alternate between running and walking.
evablogger [386]

Answer:

if marcus ran 1,600 meters that means he walked 400 meters

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Evaluate the six trigonometric functions of the angle 0.
Arturiano [62]

Given:

Right triangle

To find:

The six trigonometric functions of θ

Solution:

Hypotenuse = 18

Adjacent side to θ = 10

Opposite side to θ = ?

Using Pythagoras theorem:

\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2

18^2 =10^2+\text{opposite}^2

324=100+\text{opposite}^2

Subtract 100 from both sides.

224=\text{opposite}^2

Taking square root on both sides.

4\sqrt{14}=\text{opposite}

Using trigonometric ratio formula:

$\sin\theta =\frac{\text{opposite }}{\text{hypotenuse}}

$\sin\theta =\frac{4\sqrt{14} }{18}

$\csc\theta =\frac{\text{hypotenuse}}{\text{opposite }}

$\csc\theta =\frac{18}{4\sqrt{14} }

$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}

$\cos \theta=\frac{10}{18}

$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}

$\sec \theta=\frac{18 }{10}

$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}

$\tan \theta=\frac{4\sqrt{14} }{10}

$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}

$\cot \theta=\frac{10}{4\sqrt{14} }

8 0
3 years ago
Other questions:
  • Alex purchased a 6-hour calling card. He has used t minutes of access time. Write an algebraic expressions to represent how many
    13·2 answers
  • Penelope drove 27 kilometers. Which expression finds the distance she drove in centimeters?
    11·1 answer
  • "a man drove 10 mi directly east from his home, made a left turn at an intersection, and then traveled 2 mi north to his place o
    8·1 answer
  • Between which of the following pairs of numbers, can a rational number be found? (answer can be more than one pair)
    10·1 answer
  • What is x please help
    6·1 answer
  • What is the slope of line that contain these points ?
    9·1 answer
  • -
    7·1 answer
  • Please help asappp worth 20
    12·2 answers
  • PLS HELPPP<br> FIND X <br> I will mark braniliest
    11·1 answer
  • Find x and y.<br>help please ty:)​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!