Help with what i don’t see a pic
Answer:
28r + 8r + r = 55
Step-by-step explanation:
Some values you know (given or calculated) and some things you do not know.
RATE TIME DISTANCE
BIKE 2*8r 1.75
RUN 8r
SWIM r 1
Total 55
Give a variable to unknown running speed and fill in everything.
RATE TIME DISTANCE
BIKE 16r 1.75 28r
RUN 8r t 8rt
SWIM r 1 r
Total 55
Notice some trouble? WHY? I missed seeing the "ran for one hour". the variable t is KNOWN! This will be corrected here:
RATE TIME DISTANCE
BIKE 16r 1.75 28r
RUN 8r 1 8r
SWIM r 1 r
Total 55
Calculations used to fill out the graph:
Then her running speed was 8r,
and her biking speed was 2*(8r) = 16r.
Swimming for 1 hour, Jenny covered the distance of 1*r = r kilometers.
Biking for 1.75 hour, Jenny covered the distance of 1.75*16r = 28r kilometers.
Running for 1 hour, Jenny covered the distance of 1*2r = 8r kilometers.
Everything is filled and looks good. There is a sum of distances in just the one single variable, r.
Solve for r, and this is the swimming speed.
28r + 8r + r = 55
Answer:
6) - (7m - 4) A. [10m + (-7m)] + [(-6) + 4] B. (10m + 7m) + [(-6) + (-4)] C. [(-10m) + (-7m)] + (6 + 4) D. [10m + (-7m)] + [6 + (-4)]
Step-by-step explanation:
I’m pretty sure it’s 1640 or A.
Answer:
It would take 1 more mile if he took route Street A and then Street B rather than just Street C.
Step-by-step explanation:
Pythagorean Theorem: a² + b² = c²
We use the Pythagorean Theorem to find the length of Street C:
2² + 1.5² = c²
c = √6.25
c = 2.5
Now we find how much longer route A and B is compared to C:
3.5 - (2 + 1.5) = 3.5 - 2.5 = 1
