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puteri [66]
2 years ago
8

Find the slope of (5,-6) and (-1,8)

Mathematics
1 answer:
jeka57 [31]2 years ago
5 0

the slope is -14/6 or the simplified version is -7/3

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​ y=−8x−3 x+y=7 ​ Is (3,4)(3,4)left parenthesis, 3, comma, 4, right parenthesis a solution of the system? Choose 1 answer: Choos
kirill [66]

Given:

The system of equation is

y=-8x-3

x+y=7

To find:

Whether (3,4) is a solution of the given system or not.

Solution:

We have,

y=-8x-3          ...(i)

x+y=7            ...(ii)

Putting the value of y in (ii) from (i), we get

x+(-8x-3)=7

x-8x-3=7

-7x=7+3

-7x=10

Divide both sides by -7.

x=\dfrac{10}{-7}

x=-\dfrac{10}{7}

Putting x=-\dfrac{10}{7} in (i), we get

y=-8\times (\dfrac{-10}{7})-3

y=\dfrac{80}{7}-3

y=\dfrac{80-21}{7}

y=\dfrac{59}{7}

So, the only solution of the given system is \left(-\dfrac{10}{7},\dfrac{59}{7}\right).

Hence, (3,4) cannot be a solution of given system, Hence the correct option is B.

7 0
3 years ago
Read 2 more answers
How do i <br> Evaluate 4!.
Wewaii [24]
Hello there!

The formula is
N! = n(n -1)(n - 2)
Now all we have to do is replace N by 4
N! = 4(4-1)(4-2)
    = (4)(3)(4-2)
    = (12)(2)
    = 24 
Here you go, the answer is : 24


I hope this answer help! Good luck with your studies. 

5 0
4 years ago
Describe how the transformed function below is obtained from its parent function. y=1/x -5
cluponka [151]

Answer:

3.5y

Step-by-step explanation:

6 0
3 years ago
A student mixes two substances in a large beaker. After two hours, the student sees that the substances have separated again.
musickatia [10]

Answer:

densities

Step-by-step explanation:

6 0
3 years ago
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Which is an equation for the line that contains (-2, 5) and has a slope of -7 ?
Dmitriy789 [7]
<h3><em>H</em><em>i</em><em>i</em><em>.</em><em>.</em></h3>

<h3><em> </em><em>Let (-2 , 5) be (x1 , y1)</em></h3><h3 /><h3><em> </em><em>Slope (m) = -7</em></h3><h3 /><h3><em>Using this : (y - y1) = m(x - x1) , find the equation of line..</em></h3>

<h2><em>Have a nice time..!</em></h2>
3 0
3 years ago
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