What is the surface area, in cm2, of the figure shown above ? Round your answer to the nearest tenth .

A line goes through the points (-6, -8) and (12, 7). a) What is the slope of the line? Show your work. b) Write the equation of

kompoz [17]

m = $\frac{5}{6}$ , y - 7 = $\frac{5}{6}$ ( x - 12), y = $\frac{5}{6}$ x - 3

(a) calculate the slope using the gradient formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 6, - 8) and (x₂, y₂) = (12, 7)

m = $\frac{7+8}{12+6}$ = $\frac{15}{18}$ = $\frac{5}{6}$

(b) the equation of a line in point-slope form is

y - b = m(x - a )

where m is the slope and (a, b) a point on the line

using m = $\frac{5}{6}$ and (a , b) = (12, 7 )

y - 7 = $\frac{5}{6}$ (x - 12)

(c) the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange (b ) into this form

y - 7 = $\frac{5}{6}$ - 10

y = $\frac{5}{6}$ x - 3

3 0

4 years ago

Someone please help...due todayyy

IRISSAK [1]

Answer: I believe it is 1.1x10^-8

Step-by-step explanation:

Because 3.4x10^2 divided by 3x10^10 gives you 0.00000011 which is then converted through scientific notation into 1.1 x10^-8

4 0

3 years ago

A company is interviewing potential employees. Suppose that each candidate is either qualified, or unqualified with given probab

stira [4]

Answer:

$P(C=1|T=1)=q(\sum_{i=15}^{20}\binom{20}{i} p^i(1-p)^{20-i})( \sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i])^{-1}$

Step-by-step explanation:

Hi!

Lets define:

C = 1 if candidate is qualified

C = 0 if candidate is not qualified

A = 1 correct answer

A = 0 wrong answer

T = 1 test passed

T = 0 test failed

We know that:

$P(C=1)=q\\P(A=1 | C=1) = p\\P(A=0 | C=0) = p$

The test consist of 20 questions. The answers are indpendent, then the number of correct answers X has a binomial distribution (conditional on the candidate qualification):

$P(X=x | C=1)=f_1(x)=\binom{20}{x}p^x(1-p)^{20-x}\\P(X=x | C=0)=f_0(x)=\binom{20}{x}(1-p)^xp^{20-x}$

The probability of at least 15 (P(T=1))correct answers is:

$P(X\geq 15|C=1)=\sum_{i=15}^{20}f_1(i)\\P(X\geq 15|C=0)=\sum_{i=15}^{20}f_0(i)\\$

We need to calculate the conditional probabiliy P(C=1 |T=1). We use Bayes theorem:

$P(C=1|T=1)=\frac{P(T=1|C=1)P(C=1)}{P(T=1)}\\P(T=1) = qP(T=1|C=1) + (1-q)P(T=1|C=0)$

$P(T=1)=q\sum_{i=15}^{20}f_1(i) + (1-q)\sum_{i=15}^{20}f_0(i)\\P(T=1)=\sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i)]$

$P(C=1|T=1)=q(\sum_{i=15}^{20}\binom{20}{i} p^i(1-p)^{20-i})( \sum_{i=15}^{20}\binom{20}{i}[qp^i(1-p)^{20-i} + (1-q)p^{20-i}(1-p)^i])^{-1}$

5 0

3 years ago

Use the figure. overline SR tangent to at R. Choose the true statement

meriva

Answer:

$m\angle SRQ = 90°\\$

Step-by-step explanation:

Since, segment SR is tangent to the circle with center Q at point R.

$\therefore QR\perp SR\\\huge \red {\boxed {\therefore m\angle SRQ = 90°}} \\$

3 0

3 years ago

the red line and the blue line trains just arrived at station when will they next arrive at the station at the same time

Whitepunk [10]

They will meet back up in 40 minutes because 8x5=40 and 10x4=40 which 40 is both a multple of 8 and 10 so you're welcome

4 0

3 years ago