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seraphim [82]
1 year ago
15

Compute the probability of event E if the odds in favor of E are 28 to 29.

Mathematics
2 answers:
NeX [460]1 year ago
4 0

Answer:

28/57

Step-by-step explanation:

odds in favor of event occurring = (probability event occurs)/(probability event does not occur)

Let p = probability event occurs.

Then the probability the event does not occur is 1 - p.

Let the odds = a/b.

a/b = p/(1 - p)

a(1 - p) = bp

a - ap = bp

bp + ap = a

p(a + b) = a

p = a/(a + b)

p = 28/(28 + 29)

p = 28/57

omeli [17]1 year ago
3 0
<h3>Answer:  28/57</h3>

Explanation:

The odds in favor of 28 to 29 means there are 28 ways the event E could occur and 29 ways it doesn't occur.

So there are 28 instances out of 28+29 = 57 ways total.

It leads to the fraction 28/57 which cannot be reduced further.

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Answer:

   (\frac{8^4}{10^4} )^{-\frac{1}{4} }  = \frac{5}{4}

Step-by-step explanation:

<u><em>Explanation</em></u>

Given  

       (\frac{8^4}{10^4} )^{-\frac{1}{4} }

By using algebra formulas

  (\frac{a}{b} )^{m} = \frac{a^m}{b^n}

(\frac{8^4}{10^4} )^{-\frac{1}{4} } = \frac{(8^{4})^{\frac{-1}{4} }  }{(10^{4} )^{\frac{-1}{4} } }

(a^{m} )^{n} = a^{mn}

\frac{(8^{4})^{\frac{-1}{4} }  }{(10^{4} )^{\frac{-1}{4} } } = \frac{8^{4X\frac{-1}{4} } }{10^{4 X\frac{-1}{4} } }

          = \frac{8^{-1} }{10^{-1} }

           = \frac{10}{8} \\= \frac{5}{4}

<u><em>Final answer:-</em></u>

 (\frac{8^4}{10^4} )^{-\frac{1}{4} }  = \frac{5}{4}

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