Answer:
Given A triangle ABC in which
∠C =90°,∠A=20° and CD ⊥ AB.
In Δ ABC
⇒∠A + ∠B +∠C=180° [ Angle sum property of triangle]
⇒20° + ∠B + 90°=180°
⇒∠B+110° =180°
∠B =180° -110°
∠B = 70°
In Δ B DC
∠BDC =90°,∠B =70°,∠BC D=?
∠BDC +,∠B+∠BC D=180°[ angle sum property of triangle]
90° + 70°+∠BC D =180°
∠BC D=180°- 160°
∠BC D = 20°
In Δ AC D
∠A=20°, ∠ADC=90°,∠AC D=?
∠A + ∠ADC +∠AC D=180° [angle sum property of triangle]
20°+90°+∠AC D=180°
110° +∠AC D=180°
∠AC D=180°-110°
∠AC D=70°
So solution are, ∠AC D=70°,∠ BC D=20°,∠DB C=70°
Answer:
<u>Option C. It is zero</u>
Step-by-step explanation:
The graph represents a quadratic equation
The quadratic equation has the form ⇒a x² + b x + c
The discriminant of the quadratic equation is D = b² - 4ac
From the discriminant of the quadratic equation, we can know the type of roots of the quadratic equation.
- If D > 0 ⇒ Two real roots.
- If D = 0 ⇒ one real roots
- If D < 0 ⇒ Two imaginary roots.
The roots of the quadratic equation are the x-intercepts of the function.
As shown at the figure, the quadratic equation has only one point of intersection with the x-axis
So, the function has only one root ⇒ D = 0
So, the discriminant of the quadratic equation = 0
<u>The answer is option C. It is zero</u>
Answer:
x = -5
Step-by-step explanation:
-5(1 - 5x) +5(-8x - 2) = -4x – 8x
First lets simplify each side of the equation.
-5+25x-40x-10 = -4x-8x
Combine like terms
-15x-15=-12x
Add 15x to both sides (addition property of equality)
-15=3x
Divide each side by 3 (division property of equality)
x=-5
The answer is x = -5
4/52 = 1/13 <== here ya go
