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4 years ago

Which of the following ratios is not equivalent to 6:10? 3/5 9/15 48/80 24/45

1 answer:

4 0

The answer is 24/45

Let's check out all choices:
a) 6:10 = 3:5
6 * 5 = 10 * 3
30 = 30
Therefore, equivalent!

b) 6:10 = 9:15
6 * 15 = 10 * 9
90 = 90
Therefore, equivalent!

c) 6:10 = 48:80
6 * 80 = 10 * 48
480 = 480
Therefore, equivalent!

d) 6:10 = 24:45
6 * 45 = 10 * 24
270 ≠ 240
<u>Therefore, inequivalent!</u>

You might be interested in

Which number line represents the solutions to 1-2x1 = 4?

kaheart [24]

Answer:

Third option: $x = -2$ and $x = 2$

Step-by-step explanation:

Given:

$|-2x|=4$

For a modulus function, if $|f(x)|=a$ , then,

$f(x)=\pm a$

Here, $f(x)=-2x$ , $a=4$

∴ $-2x=\pm 4\\ -2x=-4\textrm{ or } -2x=4\\ x=\frac{-4}{-2}\textrm{ or }x=\frac{4}{-2}\\ x= 2\textrm{ or }x=-2$

Therefore, the third option is the correct answer as the graph has $x$ values as -2 and 2

8 0

3 years ago

There are 110 students in the 6th grade band and 120 students in the 7th grade band. Of the students, 60% of the 6th grade band

r-ruslan [8.4K]

Answer:

36 more students of grade 7 went on a trip than students of grade 6

Step-by-step explanation:

60 % of 110 students= 60/100*110= 66 students

85 % of 120 students= 85/100 * 120= 102 students

No of students of grade 7th more than 6th grade students= 102-66= 36

6 0

3 years ago

Create a linear function that has a rate of change of -4 and a solution at (-5,2)

san4es73 [151]

You would use the point-slope equation of y-y₁=mx(x-x₁)

So the rate of change is the slope and equals m, so m=-4

and has a solution at (-5,2) which would be the (x₁, y₁) and then it is just plugging in the numbers

y - (2) = (-4)(x - (-5))

y - 2 = -4 (x+5)

y - 2 = -4x - 20

y = -4x - 18

8 0

3 years ago

7/10 divided by -2/7

Tpy6a [65]

Answer:

1/20

Step-by-step explanation:

hope this helps

6 0

2 years ago

Read 2 more answers

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{236100}{8} = 29512.5$

Sum of squares of differences = 3408750

$S.D = \sqrt{\frac{3408750}{7}} = 697.82$

Population mean, μ = $30,000

Sample mean, $\bar{x}$ = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars}$ We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975$

Now,

$t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

8 0

4 years ago