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Neporo4naja [7]

3 years ago

14

Leila bought lunch at school. She had a sandwich and a dessert that cost $11. Her dessert cost $2.50. Solve the equation 11=s +

$2.50 to find the cost of Leila's sandwich,s . Lol

1 answer:

Llana [10]3 years ago

6 0

Answer:

8.50

Step-by-step explanation:

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Can someone please help me solve these two problems and explain them to me? About the one with proportions though... I've always

NeTakaya

Answers:

A) $-\frac{11}{4}$

C) $m_{1}=\frac{Fr^{2}}{G m_{2}}$

Step-by-step explanation:

<u>Part 1:</u>

We have the followig equation:

$\frac{x-1}{3}-\frac{x+4}{5}=\frac{4x-1}{8}$

Calculating the least common multiple (l.c.m) in the denominator in the left side of the equation, being l.c.m=15:

$\frac{5(x-1)-3(x+4)}{15}=\frac{4x-1}{8}$

Solving for the left part of the equation:

$\frac{2x-17}{15}=\frac{4x-1}{8}$

Operating with cross product:

$8(2x-17)=15(4x-1)$

Applying the distributive property:

$16x-136=60x-15$

Isolating $x$ :

$x=-\frac{121}{44}$

Dividing numerator and denominator by 11:

$x=-\frac{11}{4}$ Hence, the correct option is A

<u>Part 2:</u>

We have the followig equation:

$F=\frac{G m_{1} m_{2}}{r^{2}}$

Operating with cross product:

$Fr^{2}=G m_{1} m_{2}$

Isolating $m_{1}$ :

$m_{1}=\frac{Fr^{2}}{G m_{2}}$ Hence, the correct option is C

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I will take M as molly and S as her sister

M=x-5
S=x
M+S=37
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-5 on other becomes 0 because when you add +5 and -5 get cancels out
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Than you divide 2 on both side to get x alone so you are left with
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Now you plug x into the equation so you get
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