The rule for this one is called the difference of squares
A^2 - b ^2 = (a+b)(a-b)
Using this rule
N^2 - 62 = (n+ sqrt(62)) (n - sqrt(62))
The solution for this one is to make the statement = 0
0 = (n+ sqrt(62)) (n - sqrt(62))
N can either be +- sqrt(62)
Answer: c. (3, 7)
Step-by-step explanation:
Answer:
x=2
Step-by-step explanation:
4x+1=2x+5
-2x -2x
2x+1=5
-1 -1
2x=4
2x/2
4/2
x= 2
sorry I didn't explain better but here
Answer:
x = sqrt(11)
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2+b^2 = c^2 where a and b are the sides and c is the hypotenuse
x^2 +(sqrt(5))^2 = 4^2
x^2 +5 = 16
x^2 =16-5
x^2 = 11
Taking the square root of each side
x = sqrt(11)
Answer: -22z
Step-by-step explanation: Since both terms contain a <em>z</em>, we can subtract them since they are like terms.
So -8z- 14z simplifies to -22z.
