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telo118 [61]
3 years ago
7

How are the divisibility rules involved with the simplification of fractions?

Mathematics
1 answer:
Rashid [163]3 years ago
5 0
Because when you simplify a fraction you divide the number on bottom be the top number to simplify the fraction and make it a mixed number
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Carmen wants to join a gym. Gym A costs $26.76 plus an additional $4 for each visit.
DanielleElmas [232]
Yes the answer is ymb=y your welcome
6 0
3 years ago
The daily rainfall experienced by Soaking City has been recorded on 9 randomly selected days throughout the year. This process h
belka [17]

Answer:

0.195

Step-by-step explanation:

Given:

For ; sample size, n = 9 ;

Standard Error (S. E) = 0.39

S. E = σ / sqrt(n)

σ = standard deviation

0.39 = σ / sqrt(9)

σ = 0.39 * 3

σ = 1.17

Therefore, For n = 36

S. E = 1.17 / sqrt(36)

S.E = 1.17 / 6

S.E = 0.195

3 0
2 years ago
Your firm is contemplating the purchase of a new $570,000 computer-based order entry system. The system will be depreciated stra
Galina-37 [17]

Answer:

IRR = 31.93%

Step-by-step explanation:

Depreciation = 570,000/5 = 114,000

<u>Calculation of Operating cash flow</u>

Operating income = 270000 - 114000 = 156,000

Tax = 156,000 * 35% = 54,600

Operating cash flow = Operating income + Depreciation - Tax = 156,000 + 114,000 - 54,600 = 215,400

<u>Calculation of initial investment</u>

CF0 = Initial investment - Working capital = 570,000 - 73,000 = 497,000

<u>Calculation of the last year cash flow</u>

CF5 = OCF + After tax salvage - Net working capital = 215,400 + 37,000 - 73,000 = 180,100

<u>Calculation of IRR</u>

IRR for the project = IRR(Cashflow from year0, 1, 2,3,4,5) <em>"as attached below picture below"</em>

IRR for the project = 31.93%

8 0
2 years ago
Show that for any positive numbers a and b with a ≠ 1 and b ≠ 1, loga(b) ∙ logb(a) = 1.
elena55 [62]

Answer:

logₓ(y) = \frac{\log(y)}{\log(x)}

\frac{\log(b)}{\log(a)}\times\frac{\log(a)}{\log(b)}

or

= 1

Step-by-step explanation:

Data provided:

a ≠ 1 and b ≠ 1

To prove \log_a(b).\log_b(a)=1

RHS = 1

LHS = \log_a(b).\log_b(a)

Now,

We have the property of the log function as:

logₓ(y) = \frac{\log(y)}{\log(x)}

applying the above property on the LHS side to solve LHS, we get

LHS = \frac{\log(b)}{\log(a)}\times\frac{\log(a)}{\log(b)}

or

LHS = 1

Since,

LHS = 1 is equal to the RHS = 1

Hence, proved that  \log_a(b).\log_b(a)=1

7 0
3 years ago
Solve the system of linear equations using either substitution or the elimination method.
Lelechka [254]

Answer:

x=2;y=2

Step-by-step explanation:

2x+y=6..........1

3x-y=4............2

adding equation1 with equation 2

2x+y+3x-y=6+4

5x=10

x=10/5=2

substituting vslue of y in equation 1

2×2+y=6

y=6-4

y=2

4 0
2 years ago
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