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Gnesinka [82]
2 years ago
7

In the given figure find the value of x.​

Mathematics
1 answer:
jek_recluse [69]2 years ago
5 0

Answer:

It needs to equal 180 so just do that

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The circle is inscribed in triangle A E C. Which are congruent line segments? Select two options. AB and CB ;EF and ED; ED and C
qaws [65]

Answer:

B and E

aka

E-F and E-D

C-B and C-D

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The following data points are the number of games pitched by each of the Greenbury Goblins' starting pitchers last season.
Leviafan [203]

Answer: 1.87 games

Step-by-step explanation:

step 1 ; x= 3+2+4+7 divide 4 = 16/4 = 4 games

5 0
3 years ago
Can you guys please help!
yuradex [85]

Answer:

5 for the first and 4x for the second one also plz give heart

Step-by-step explanation:

i just know

4 0
3 years ago
HELP ASAP TEST IS OMOST OVER!!!!!!!!!!
svet-max [94.6K]

Answer: C)46 ft

Step-by-step explanation:

We know that the circumference of a circle can be calculated with this formula:

C=2\pi r

Where "r" is the radius of the circle.

Since John is putting a fence around his garden that is shaped like a half circle and a rectangle, then we can find how much fencing he needs by making this addition:

Fencing=\frac{2\pi r}{2}+2l+w

Where "l" is the lenght of the rectangle and "w" is the width of the rectangle.

Since we know that the radius of the circle is half its diameter, we can find "r". This is:

r=\frac{7ft}{2}=3.5ft

Then, substituting values (and using \pi=\frac{22}{7}), we get:

Fencing=\frac{2(\frac{22}{7})(3.5ft)}{2}+2(14ft)+7ft=46ft

4 0
3 years ago
Read 2 more answers
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
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