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Zina [86]
2 years ago
15

Simplify the polynomial and evaluate for the following values. x^2 yxy-xy^2xy if x=-3 and y=2 the simplified polynomial is = , T

he value is
Mathematics
1 answer:
Alinara [238K]2 years ago
4 0

Answer:

The simplified polynomial is x^3 y^2 -x^2 y^3 +xy

The value is -186

Step-by-step explanation:

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Find the greatest number of children to whom 260 pens and 364 chocolates can be divided equally.
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answer:

52

explanation:

52 is the highest shared factor of the two numbers.

52*5=260

52*7=364

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What is the decimal equivalent o the rational number 6/11
koban [17]
Divide 6 by 11: 6/11=.5454545 :)
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kotegsom [21]

Answer:

k, a, and i  I think!

Step-by-step explanation:

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CAN ANYBODY HELP ME OUT
bija089 [108]

Answer:

Correct option is

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

Step-by-step explanation:

Here, we are given the line RQ, which is divided in two equal parts by a line PS which is perpendicular to RQ.

The foot S of PS is on the line RQ.

First of all, let us do a construction here.

Join the point R with P and P with Q.

Please refer to the attached image.

Now, let us consider the triangles  PQS and PRS:

  • Side QS = RS (as given)
  • \angle PSR = \angle PSQ = 90^\circ
  • Side PS = PS (Common side in both the triangles)

Now, Two sides and the angle included between the two triangles are equal.

So by SAS congruence we can say that \triangle PRS \cong \triangle PQS

Therefore, the corresponding sides will also be equal.

RP = QP

RP is the distance between R and P.

QP is the distance between Q and P.

Hence, to prove that P is equidistant from R and Q, we have proved that:

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

7 0
3 years ago
Which features of figure JKLM remain the same after any rigid transformation? I-ready
Levart [38]

Answer: size and shape

Step-by-step explanation:i got it right on the quiz

8 0
2 years ago
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