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zaharov [31]
3 years ago
6

W trójkącie ABC połączono wierzchołek C z punktem D który jest środkiem boku AB . Wyznaczono równierz środek odcinka CD punkt E

Uzasadni że trójkąty ACE i BED mają równe pola
Prosze szybkoo

Mathematics
1 answer:
qwelly [4]3 years ago
8 0
Translate into English please
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Solve system of equation by elimination:
mars1129 [50]

Answer:

a. (4, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

-x + 4y = -8

-5x - 4y = -16

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Elimination</em>

  1. Combine equations:                     -6x = -24
  2. Isolate <em>x</em>:                                        x = 4

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define equation:                   -x + 4y = -8
  2. Substitute in <em>x</em>:                      -4 + 4y = -8
  3. Isolate <em>y</em> term:                       4y = -4
  4. Isolate <em>y</em>:                                y = -1
4 0
2 years ago
Read 2 more answers
Prove: If C⊂A and D⊂B then D−A⊂B−C
nalin [4]
Let x\in D\setminus A, so that x\in D but x\not\in A. Since D\subset B, it follows that x\in B, and since C\subset A, it follows that x\not\in C, which means x\in B\setminus C.
3 0
2 years ago
a machinest can produce 114 parts in 6 minutes.at this rate,how many parts can the machinist produce in 15 minutes
JulsSmile [24]

The first thing we need to do is find the rate of parts for 15 minutes.

So, we divide 114 parts per 6 minutes and get 19 parts per minute


Then we multiply this rate per minute by 15 minutes

The answer is 285


Attached Work Below:

Part1\\114\div6=19\\\\Part 2\\19\times15=285

7 0
2 years ago
Read 2 more answers
Express sin A, cos A, and tan A as ratios ​
vlabodo [156]
<h3>Answer: Choice B</h3><h3>sqrt(3)/2,    1/2,   sqrt(3)</h3>

================================================

Explanation:

Sine of an angle is the ratio of the opposite side over the hypotenuse. For reference angle A, the opposite side is BC = 6sqrt(3). The hypotenuse is the longest side AB = 12

Sin(angle) = opposite/hypotenuse

sin(A) = BC/AB

sin(A) = 6sqrt(3)/12

sin(A) = sqrt(3)/2

---------------

Cosine is the ratio of the adjacent and hypotenuse

cos(angle) = adjacent/hypotenuse

cos(A) = AC/AB

cos(A) = 6/12

cos(A) = 1/2

---------------

Tangent is the ratio of the opposite and adjacent

tan(angle) = opposite/adjacent

tan(A) = BC/AC

tan(A) = 6sqrt(3)/6

tan(A) = sqrt(3)

5 0
3 years ago
g Make a decision about the given claim. Use only the rare event​ rule, and make subjective estimates to determine whether event
vagabundo [1.1K]

Answer:

There is not sufficient evidence to support the claim.

Step-by-step explanation:

The claim to be tested is:

The mean respiration rate (in breaths per minute) of students in a large statistics class is less than 32.

To test this claim the hypothesis can be defined as follows:

<em>H₀</em>: The mean respiration rate of students is 32, i.e. <em>μ</em> = 32.

<em>Hₐ</em>: The mean respiration rate of students is less than 32, i.e. <em>μ</em> < 32.

The sample mean  respiration rate of students is 31.3.

According to the claim the sample mean is less than 32.

The sample mean value is not unusual if the claim is true, and the sample mean value is also not unusual if the claim is false.

Thus, there is not sufficient evidence to support the claim.

7 0
2 years ago
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