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zaharov [31]
4 years ago
6

W trójkącie ABC połączono wierzchołek C z punktem D który jest środkiem boku AB . Wyznaczono równierz środek odcinka CD punkt E

Uzasadni że trójkąty ACE i BED mają równe pola
Prosze szybkoo

Mathematics
1 answer:
qwelly [4]4 years ago
8 0
Translate into English please
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Al lives 30 mi. from Ann. At the same time, they start biking toward each other on the same road. Al’s constant rate is 12 mph.
dolphi86 [110]
C. 1.5 hours. divide 12 by 8, and you get 1.5.
4 0
3 years ago
Can someone please help meee
pshichka [43]

Answer:

160

Step-by-step explanation:

Angle ABE is a 180 as ABE forms a line

so angle ABC + ANGLE CBE = 180

x + 20 = 180

x = 180-20

= 160

I hope im right!!

6 0
3 years ago
Read 2 more answers
A building 84 ft high casts a 46 ft shadow. How tall is a building that casts a 110 ft shadow at the same time of the day? (to t
Bond [772]
The ratio of building heights will be the same as the ratio of shadow lengths.
  (taller building)/(shorter building) = (longer shadow)/(shorter shadow)
  (taller building)/(84 ft) = (110 ft)/(46 ft) . . . . . . fill in the given numbers
  (taller building) = (84 ft)*(110/46) ≈ 200.9 ft . . multiply by 84 ft, evaluate

The appropriate selection is
  D) 200.9 ft
4 0
3 years ago
Read 2 more answers
Suppose you want to fence in some land along the edge of a straight river. the fenced area will be in the shape of a rectangle,
m_a_m_a [10]
For the largest area, half the fence is used parallel to the river, and the other half is used for the two ends of the rectangular space.

The dimensions are 475 m by 237.5 m.

_____
Let x represent the length along the river. Then the area (A) is found as
.. A = x*(950 -x)/2
This equation describes a parabola with its vertex (maximum) halfway between the zeros of x=0 and x=950. That is, the maximum area is achieved when half the fence is used parallel to the river.

7 0
4 years ago
write the equation of a line that is perpendicular to the given line and that passes through the given point. y-4=5/2(x+3) ; (-7
faltersainse [42]
The gradient of the perpendicular line would be the negative reciprocal of the original line. Therefore the gradient of the perpendicular line would be -2/5x.
Since we know y=mx+c, ∴y=-2/5x+c. Sub in the x and y values of the given point and we get that c=26/5.

The perpendicular equation would be y=-2/5x+26/5.
I hope I got this right.
7 0
4 years ago
Read 2 more answers
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