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antoniya [11.8K]
3 years ago
13

C(squared)L(squared) + 100v(squared) = 100c(squared)I have to solve for L

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
8 0

Answer:

L = ±√( (100c² - 100v²) / C² )

Step-by-step explanation:

You're just doing reverse PEMDAS.

So first get all the values correlated with L on one side and the non-L values on the other side using subtraction/addition.

Then remove all coefficient using multiplication/division.

Then take the sqareroot to get rid of the squre on the v.

Remember that taking squareroot gives a ± answer because

(x)² = (-x)²

jeyben [28]3 years ago
7 0
First subtract 100v² from both sides to get:

C²L²=100c²-100v²

Then divide both sides by C²:

L²=(100c²-100v²)/C²

Then take the square root of both sides:

L=+ or - the square root of (100c²-100v²)/C²
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What is EG? Round to the nearest tenth if necessary.
slava [35]

Answer:

26.

Step-by-step explanation:

As the vertex angles are equal:

24/54 = x / x+10

54x = 24x + 240

30x = 240

x = 8

So EG = x + x + 10

=  8 + 8 + 10

= 26..

7 0
3 years ago
During a hike, 3 friends equally shared 1/2 pound of trail mix. What amount of trail mix, in pounds, did each friends recieve 1/
AleksandrR [38]

Answer:

0.1666

Step-by-step explanation:

7 0
3 years ago
Help please rn help
aksik [14]

Area of the large semicircle

= \pi{r}^{2}  \div 2

=  \frac{22}{7}  \times 12 {}^{2}  \times  \frac{1}{2}

=  \frac{11}{7}  \times12 \times 12

=  \frac{11}{7}  \times 144

= 226.28

Area of the small semicircle

= \pi  {r}^{2}  \div 2

=  \frac{22}{7}  \times 6 {}^{2}  \times  \frac{1}{2}

=  \frac{11}{7}  \times 6 \times 6

=  \frac{11}{7}  \times 36

= 56.57

Area of the figure

= 226.28 - 56.57

= 169.71 {cm}^{2}

8 0
3 years ago
There are 24 students in mr bobs math class 5/8 of these students earned an a on the geometry assessment how many students earne
dlinn [17]
Of means multiply

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15 students earned an A
8 0
4 years ago
aron lei is making identical balloon arrangements for a party. He has 32 maroon balloons and 24 white balloons, he wants each ar
alexandr402 [8]

Answer:

The greatest number of arrangements that he can make if every balloon is used is 8.

Step-by-step explanation:

The greatest number of arrangements will be the greatest common factor between 24 and 32.

GCF of 24 and 32:

We keep factoring both numbers by prime factors, while they can both be divided by the same number. So

24 - 32|2

12 - 16|2

6 - 8|2

3 - 4

There is no factor for which we can divide both 3 and 4. So the GCF is 2*2*2 = 8.

This means that the greatest number of arrangements that he can make if every balloon is used is 8.

5 0
3 years ago
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