C(squared)L(squared) + 100v(squared) = 100c(squared)I have to solve for L

Mathematics

2 answers:

oksian1 [2.3K]2 years ago

8 0

Answer:

L = ±√( (100c² - 100v²) / C² )

Step-by-step explanation:

You're just doing reverse PEMDAS.

So first get all the values correlated with L on one side and the non-L values on the other side using subtraction/addition.

Then remove all coefficient using multiplication/division.

Then take the sqareroot to get rid of the squre on the v.

Remember that taking squareroot gives a ± answer because

(x)² = (-x)²

jeyben [28]2 years ago

7 0

First subtract 100v² from both sides to get:

C²L²=100c²-100v²

Then divide both sides by C²:

L²=(100c²-100v²)/C²

Then take the square root of both sides:

L=+ or - the square root of (100c²-100v²)/C²

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dem82 [27]

<h3><u>Explanation</u></h3>

Given the system of equations.

$\begin{cases} 6x - 2y = 10 \\ x - 2y = - 5 \end{cases}$

Solve the system of equations by eliminating either x-term or y-term. We will eliminate the y-term as it is faster to solve the equation.

To eliminate the y-term, we have to multiply the negative in either the first or second equation so we can get rid of the y-term. I will multiply negative in the second equation.

$\begin{cases} 6x - 2y = 10 \\ - x + 2y = 5 \end{cases}$

There as we can get rid of the y-term by adding both equations.

$(6x - x) + ( - 2y + 2y) = 10 + 5 \\ 5x + 0 = 15 \\ 5x = 15 \\ x = \frac{15}{5} \longrightarrow \frac{ \cancel{15}}{ \cancel{5}} = \frac{3}{1} \\ x = 3$

Hence, the value of x is 3. But we are not finished yet because we need to find the value of y as well. Therefore, we substitute the value of x in any given equations. I will substitute the value of x in the second equation.

$x - 2y = - 5 \\ 3 - 2y = - 5 \\ 3 + 5 = 2y \\ 8 = 2y \\ \frac{8}{2} = y \\ y = \frac{8}{2} \longrightarrow \frac{ \cancel{8}}{ \cancel{2}} = \frac{4}{1} \\ y = 4$