Answer:
7
Step-by-step explanation:
The average rate of change of f(x) in the close interval [ a, b ] is
Here [ a, b ] = [2, 5 ]
f(b) = f(5) = 2(5)² - 7(5) = 50 - 35 = 15
f(a) = f(2) = 2(2)² - 7(2) = 8 - 14 = - 6, thus
average rate of change = 
= 
= 7
Answer:
We conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
Step-by-step explanation:
We know that the perimeter of a rectangle = 2(l+w)
i.e.
P = 2(l+w)
Here
Given that the length and width of the playground by a scale factor of 2
A scale factor of 2 means we need to multiply both length and width by 2.
i.e
P = 2× 2(l+w)
P' = 2 (2(l+w))
= 2P ∵ P = 2(l+w)
Therefore, we conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
Answer:
4
4+4-4=4 im not sure actually D:
Rectangle Formula: a = lw (Area = Length x Width)
Trapezium: A= a+b/2h (Area = Area + Base / 2 x h)
I hope this helps. :)
