Answer:
C) High temperature of the day and number of zoo visitors that day
Step-by-step explanation:
Correlation describes the relationship between two quantitative variables and both variables are quantitative.

To find the gradient of the tangent, we must first differentiate the function.

The gradient at x = 0 is given by evaluating f'(0).

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.
The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:
Answer:
no
Step-by-step explanation:
75:3=25:1
140:4=45:1