Question

An object accelerates from rest at a constant rate covering a distance of 12 meters in 4 seconds. What is its rate of acceleration?
Put your answer in this form:

X.X (m/s)/s

Answer 1

Answer:

3/2

Explanation:

$d = \frac{1}{2} a {t}^{2} + vt \\ d = 12 \\ t = 4 \\ v = 0 \\ \\ 12 = \frac{1}{2} \times 16a + 0 \\ a = \frac{12}{8} = \frac{3}{2} \frac{m}{ {s}^{2} }$