Answer:
Following are the solution to the given question.
Explanation:
Please find the graph image in the attachment file.
The heat is then transferred to water from the burned cake. The temperature difference is being used to calculate the heat energy of the cookie. Transfer of energy is the move in energy from place to place. Whereas the total quantity of energy may well be moved or converted – it is named energy preservation – does not change.
D.
The gravitational of a body is possessed by the body due to the virtue of its position.
The formula for gravitational potential energy is,
P.E = mgh joules
Substituting the values
196*9.8*250= 49k
Answer:
a) r=4.24cm d=1 cm
b) ![Q=5x10^{-10} C](https://tex.z-dn.net/?f=Q%3D5x10%5E%7B-10%7D%20C)
Explanation:
The capacitance depends only of the geometry of the capacitor so to design in this case knowing the Voltage and the electric field
![V=1.00x10^{2}v\\E=1.00x10^{4} \frac{N}{C}](https://tex.z-dn.net/?f=V%3D1.00x10%5E%7B2%7Dv%5C%5CE%3D1.00x10%5E%7B4%7D%20%5Cfrac%7BN%7D%7BC%7D)
![V=E*d\\d=\frac{V}{E}\\d=\frac{1.0x10^{2}}{1.0x10^{4}}\\d=0.01m](https://tex.z-dn.net/?f=V%3DE%2Ad%5C%5Cd%3D%5Cfrac%7BV%7D%7BE%7D%5C%5Cd%3D%5Cfrac%7B1.0x10%5E%7B2%7D%7D%7B1.0x10%5E%7B4%7D%7D%5C%5Cd%3D0.01m)
The distance must be the separation the r distance can be find also using
![C=\frac{Q}{V_{ab}}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7BQ%7D%7BV_%7Bab%7D%7D)
But now don't know the charge these plates can hold yet so
a).
d=0.01m
![C=E_{o}*\frac{A}{d}\\A=\frac{C*d}{E_{o}}](https://tex.z-dn.net/?f=C%3DE_%7Bo%7D%2A%5Cfrac%7BA%7D%7Bd%7D%5C%5CA%3D%5Cfrac%7BC%2Ad%7D%7BE_%7Bo%7D%7D)
![A=\frac{5pF*0.01m}{8.85x10^{-12}\frac{F}{m}}\\A=5.69x10^{-3}m^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B5pF%2A0.01m%7D%7B8.85x10%5E%7B-12%7D%5Cfrac%7BF%7D%7Bm%7D%7D%5C%5CA%3D5.69x10%5E%7B-3%7Dm%5E%7B2%7D)
![A=\pi *r^{2}\\r=\sqrt{\frac{A}{r}}\\r=\sqrt{\frac{5.64x10^{-3}m^{2} }{\pi } } \\r=42.55x^{-3}m](https://tex.z-dn.net/?f=A%3D%5Cpi%20%2Ar%5E%7B2%7D%5C%5Cr%3D%5Csqrt%7B%5Cfrac%7BA%7D%7Br%7D%7D%5C%5Cr%3D%5Csqrt%7B%5Cfrac%7B5.64x10%5E%7B-3%7Dm%5E%7B2%7D%20%7D%7B%5Cpi%20%7D%20%7D%20%20%5C%5Cr%3D42.55x%5E%7B-3%7Dm)
b).
![C=\frac{Q}{V_{ab}}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7BQ%7D%7BV_%7Bab%7D%7D)
![Q=C*V\\Q=5x10^{-12} F*1x10^{2}\\Q=5x10^{-10}C](https://tex.z-dn.net/?f=Q%3DC%2AV%5C%5CQ%3D5x10%5E%7B-12%7D%20F%2A1x10%5E%7B2%7D%5C%5CQ%3D5x10%5E%7B-10%7DC)
Answer:
<h3>3km</h3>
Explanation:
To get the displacement, we will make use of the expression;
![D = \sqrt{(\sum d_x)^2+(\sum d_y)^2}](https://tex.z-dn.net/?f=D%20%3D%20%5Csqrt%7B%28%5Csum%20d_x%29%5E2%2B%28%5Csum%20d_y%29%5E2%7D)
Taking the sum of the distances along the x;
dx = 1km - 4km
dx = -3km
Taking the sum of the distances along the y axis
dy = 3km - 3km
dy = 0km
Substitute into the formula above;
![R = \sqrt{(-3)^2+(0)^2}\\R = \sqrt{9} \\R = 3km\\](https://tex.z-dn.net/?f=R%20%3D%20%5Csqrt%7B%28-3%29%5E2%2B%280%29%5E2%7D%5C%5CR%20%3D%20%5Csqrt%7B9%7D%20%5C%5CR%20%3D%203km%5C%5C)
Hence his displacement is 3km