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ra1l [238]
3 years ago
15

"An empty cylindrical barrel is open at one end and rolls without slipping straight down a hill. The barrel has a mass of 19.0 k

g,19.0 kg, a radius of 0.260 m,0.260 m, and a length of 0.650 m.0.650 m. The mass of the end of the barrel equals a fifth of the mass of its side, and the thickness of the barrel is negligible. The acceleration due to gravity is ????
Physics
1 answer:
Sophie [7]3 years ago
5 0

Answer:

the acceleration due to gravity, g of the cylinder is 9.81m/s2

Explanation:

since the cylinder is rolling down from a hill, the acceleration due to gravity of any object coming down from the atmosphere is always constant which is g=9.8m/s2 or approximately 10m/s2

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3 years ago
A 64.0 kg pole vaulter running at 10.2 m/s vaults over the bar. If the vaulter's horizontal component of velocity over the bar i
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Answer:

h = 5.05 m

Explanation:

given,

mass of pole vaulter, m = 64 Kg

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horizontal component of velocity in air, v = 1 m/s

height of the jump,h = ?

using energy conservation

     E_i = E_f

\dfrac{1}{2}mv_i^2 + m g h_i= \dfrac{1}{2}mv_f^2+m g h_f

initial height of the vaulter is equal to zero.

\dfrac{1}{2}v_i^2 = \dfrac{1}{2}v_f^2+gh_f

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height of the jump is equal to 5.05 m.

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