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ra1l [238]
3 years ago
15

"An empty cylindrical barrel is open at one end and rolls without slipping straight down a hill. The barrel has a mass of 19.0 k

g,19.0 kg, a radius of 0.260 m,0.260 m, and a length of 0.650 m.0.650 m. The mass of the end of the barrel equals a fifth of the mass of its side, and the thickness of the barrel is negligible. The acceleration due to gravity is ????
Physics
1 answer:
Sophie [7]3 years ago
5 0

Answer:

the acceleration due to gravity, g of the cylinder is 9.81m/s2

Explanation:

since the cylinder is rolling down from a hill, the acceleration due to gravity of any object coming down from the atmosphere is always constant which is g=9.8m/s2 or approximately 10m/s2

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Answer:

When a cyclone continues to be out over the ocean, the winds and huge waves that area unit created by the storm become dangerous for ships and alternative water vessels. ... once the cyclone approaches land it will cause an enormous quantity of injury. Flooding caused by storm surges is one among the foremost dangerous components of a cyclone.

8 0
2 years ago
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A 7.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wi
Anvisha [2.4K]

Answer:

(a) 1.075 N

(b) 4.254 T

Explanation:

(a)

From the question,

Power = Force×Velocity.

P = Fv................... Equation 1

Where P = Power dissipated in the circuit, F = Pulling force of the wire, v = speed of the wire.

make F the subject of the equation

F = P/v................. Equation 2

Given: P = 4.30 W, v = 4.0 m/s.

Substitute into equation 2

F = 4.30/4

F = 1.075 N.

(b)

Applying,

F = BILsinФ.............. Equation 2

Where B = Strength of the magnetic field, I = current in the wire, L = Length of the wire, Ф = angle between the wire and the magnetic field.

make B the subject of the equation

B = F/ILsinФ................... Equation 3

But,

P = I²R...................... Equation 4

Where R = resistance of the wire.

make I the subject of the equation

I = √(P/R)............... Equation 5

Given: P = 4.30 W, R = 0.330 Ω

Substitute into equation 5

I = √(4.3/0.33)

I = √13.03

I = 3.61 A.

Also given: L = 7 cm = 0.07 m, Ф = 90°

Substitute into equation 3

B = 1.075/(0.07×3.61×sin90)

B = 1.075/0.2527

B = 4.254 T.

4 0
3 years ago
A baseball is travelling towards a player's bat with a speed of 40.0 m/s. After being hit by the bat, the baseball is travelling
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3 0
2 years ago
a student pushes a 40-N block across the floor for a distance 0f 10 m how much work was done to move the block?
slava [35]
W=f*d
= 40N * 10m
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6 0
2 years ago
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The impact time for a particular collision is 3.0 x 10^-3 seconds and the impulse in the collision is 0.30 newton seconds. What
BartSMP [9]

<u>Answer</u>

C.) 1.0 x 10^2 Newton’s


<u>Explanation</u>

The Newton's second law of motion states that, the rate of change of momentum is proportional to the force producing it.

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but t = 3.0 x 10⁻³ seconds

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8 0
3 years ago
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