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pashok25 [27]
3 years ago
5

Explain the origin of earth's motion based on the origin of the galaxy and its solar system?

Physics
1 answer:
slava [35]3 years ago
5 0

There are numerous theories as to the origin of our galaxy and our solar system within our galaxy.  I have attached two references that will detail several of them.

As far as motion of the earth, our planet has a prograde revolution around the sun. Prograde motion would be a counterclockwise motion.  All the planets in our solar system have this prograde revolution.  They all accomplish this revolution in the same plane.  Most all the planets have a prograde roatation, like earth, as they perform this revolution.

One of the theories about how the universe and the galaxies and solar systems were formed after the Big Bang is a theory called the "nebular theory."  A nebula is a gas and dust cloud.  According to this theory, the gas and dust particles collided with each other, were gravitationally attracted to each other, and got progressively larger.  As this formation happened, a centripetal force was created by the force of the collisions and the mass of planets began to spin and revolve.  It should be noted there is room for the revolutions and rotations to go one way or another, depending on the angle of incidence in the collision of said gas and dust particles.  This would be one accounting for the present motion of the planetary constituents in our solar system.

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4 years ago
The width of a nuclear state is found to be 10^-2 ev. The corresponding lifetime of this state is?
Lelechka [254]

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7 0
2 years ago
N april 1974, steve prefontaine completed a 10-km race in a time of 27 min, 43.6 s. suppose \"pre\" was at the 7.15-km mark at a
aliya0001 [1]

solution:speed is 7.99km ,u=\frac{7990}{(25\times60)}=5.33m/s\\
now let the final velocity after 60s from 7.99km is v.\\
v-u =at\\v=5.33+a\times60\\  =60s+5.33\\now distance travelled during this time will be\\
s_{2}=vt\\
v\times103.6\\
=(60a+5.33)\times103.6\\
=551.84+6216am\\
now total distance travelled  is \\  also\\
s_{1}=ut+(\frac{1}{2})at^{2}      =5.33\times60+(0.5)9\times3600\\
=1800a+319.6m\\
Now the remaining time to complete rest race was\\
t=(27\times60+43.6)60-60(25\times60)\\
=103.6s\\Now, distance travelled during this time will be\\
s_{2}=vt\\
v\times103.6\\
=(60a+5.33)\times103.6\\
=551.84+6216am\\
now total distance travelled  is \\
s_{1}+s_{2}+7990=10000\\
1800a+319.6+551.84+6216a=2010\\
8016a=2010-871.44\\
8016a=1138.56\\
a=0.142m/s^2

6 0
3 years ago
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6 0
4 years ago
Read 2 more answers
A string with tension Ft= 10 N, with one end pinned and the other end free, is used to produce a wave supplied by a driving freq
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