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olga_2 [115]
3 years ago
9

F(x) = 5x-2, find f(-3/5) what is the output of the given input

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
4 0
F(x) = 5x - 2
f(-3/5) = 5(-3/5) - 2
f(-3/5) = -15/5 - 2
f(-3/5) = -3 - 2
f(-3/5) = -5
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7 0
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Please can I have an explanation also, I am terrible at these kinds of questions!
wlad13 [49]

Answer:

<em>The fraction of the beads that are red is</em>

Step-by-step explanation:

<u>Algebraic Expressions</u>

A bag contains red (r), yellow (y), and blue (b) beads. We are given the following ratios:

r:y = 2:3

y:b = 5:4

We are required to find r:s, where s is the total of beads in the bag, or

s = r + y + b

Thus, we need to calculate:

\displaystyle \frac{r}{r+y+b}       \qquad\qquad    [1]

Knowing that:

\displaystyle \frac{r}{y}=\frac{2}{3}      \qquad\qquad    [2]

\displaystyle \frac{y}{b}=\frac{5}{4}

Multiplying the equations above:

\displaystyle \frac{r}{y}\frac{y}{b}=\frac{2}{3}\frac{5}{4}

Simplifying:

\displaystyle \frac{r}{b}=\frac{5}{6}       \qquad\qquad    [3]

Dividing [1] by r:

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+y/r+b/r}

Substituting from [2] and [3]:

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+3/2+6/5}

Operating:

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{\frac{10+3*5+6*2}{10}}

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{10+15+12}

\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{37}

The fraction of the beads that are red is \mathbf{\frac{10}{37}}

8 0
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