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tangare [24]
2 years ago
8

Question in picture below

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
7 0

Answer:

wait ik who u are we go to the same school

Step-by-step explanation:

eekk I think I'm in ur math class yeaa I definitely know u but my name is not actually brook I just changed it

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What is an equation of the line that passes through the points ( −4 , − 6 ) and (4,4)?
kherson [118]

Answer:

y=5/4x-1

Step-by-step explanation:

-6-4/-4-4 = -10/-8 = 5/4 (slope)

y=5/4x+b

4=5/4(4)+b

b=-1

y=5/4x-1

4 0
3 years ago
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Intr un album numarul de fotografii s a micsorat cu 50%. Cu cat trebuie sa se mareasca pentru a reveni la numarul initial? Raspu
hodyreva [135]

Răspuns:

100%

Explicație pas cu pas:

Permiteți numărul inițial de fotografii = x

x - 50% din x = x - 0,5x = 0,5x

0,5x + câte% din 0,5x = x

x - 0,5x = y% de 0,5x

0,5x / 0,5x = 1

Prin urmare,

100% = 1

Prin urmare, x trebuie mărit cu 100% pentru a reveni la numărul original.

3 0
3 years ago
A college surveys local businesses about the importance of students as customers. The college chooses 150 businesses at
GenaCL600 [577]

The proportion of businesses who did not respond = 54.67%

Given : Total businesses = 150

Businesses responded = 68

Businesses did not respond =  150- 68 = 82

The proportion of businesses who did not respond =

82/150 x 100

54.67%

8 0
3 years ago
Allometric relations often can be modeled by ​f(x)= x^b​, where a and b are constants. One study showed that for a male fiddler
dolphi86 [110]

Answer:

a) f(2)= 0.448 (2)^{1.21}= 1.036 grams

b) 0.5 = 0.448 x^{1.21}

Dividing both sides by 0.448 we got:

\frac{0.5}{0.448} = x^{1.21}

We can appy the exponent \frac{1}{1.21} in both sides of the equation and we got:

(\frac{0.5}{0.448})^{\frac{1}{1.21}} = x= 1.095grams

Step-by-step explanation:

For this case we know the following function:

f(x) = 0.448 x^{1.21}

The notation is: x is the weight of the crab in​ grams, and the output​ f(x) is the weight of the claws in grams.

Part a

For this case we just need to replace x = 2 gram in the function and we got:

f(2)= 0.448 (2)^{1.21}= 1.036 grams

Part b

For this case we know tha value for f(x) =0.5 and we want to find the value of x who satisfy this condition:

0.5 = 0.448 x^{1.21}

Dividing both sides by 0.448 we got:

\frac{0.5}{0.448} = x^{1.21}

We can appy the exponent \frac{1}{1.21} in both sides of the equation and we got:

(\frac{0.5}{0.448})^{\frac{1}{1.21}} = x= 1.095grams

8 0
3 years ago
Factor -24a3b3c3 - 84a4b2c.
My name is Ann [436]
The answer is B. It’s not too difficult

4 0
3 years ago
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