The sides of a rhombus are equal length, so you have
... 5x + 20 = 6x + 10
... 10 = x . . . . . . . . subtract 5x+10
Then the side lengths are
... 5·10 +10 = 70
Two supplementary angles are in the ratio 3:7. Find the angles ?
Let the two angles be 3x and 7x.
Supplementary angles add up to 180 degrees.
Therefore:
3x + 7x = 180
10x = 180
x = 18
3x = 3 * 18 = 54
7x = 7 * 18 = 126
Answer:
19 = x
Step-by-step explanation:
The square of the tangent segment = The product of (whole secant segment) (the outside part of the secant segment)
BD²= (BA)(BE)
8² = (4 + x - 7) (4) BA = BE + EB
8² = (x - 3)(4)
64 = 4x - 12
64 + 12 = 4x
76 = 4x
19 = x
Answer:87/8
Step-by-step explanation:cause i smart :D
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Answer:
forty-five and six tenths
Step-by-step explanation:
45 = forty five
.6 = six tenths
