<span>Lets find the volume of a cylinder with a diameter D=10 inches and lenght L= 20 inches. First we need to notice that the diameter is twice the size of the radius: D=2r. Then we write the equation for the volume of the cylinder. it is the base times the height: V=pi*r^2 * L. Now we input the nubmers in the equation: V=3.14*(D/2)^2 * L where r=D/2=5 inches and after calculating we get: V=1570 inches^3</span>
Answer:
C
Step-by-step explanation:
Add 10x to both sides:
-10x - 135 = 117 + 2x
-10x - 135 + 10x = 117 + 2x + 10x
-135 = 117 + 12x
Subtract 117 from both sides:
-135 - 117 = 117 + 12x - 117
-252 = 12x
Divide both sides by 12:

-21 = x
So the answer is C.
Hope this helps!
Answer:
x = variable
3 = coefficient
1 = constant
3x^2-4x+1 = algebraic expression
2 = degree
Step-by-step explanation:
variables are typically the letters in equations (usually x and y)
coefficients are the numbers attached to the variables
constants don't have any variables attached
algebraic expressions are the full expression
degrees are the small numbers in the top right corners on either constants, variables or coefficients
Hope this helps!
Answer:
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Step-by-step explanation:

We want to find
such that
. This means



Integrating both sides of the latter equation with respect to
tells us

and differentiating with respect to
gives

Integrating both sides with respect to
gives

Then

and differentiating both sides with respect to
gives

So the scalar potential function is

By the fundamental theorem of calculus, the work done by
along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it
) in part (a) is

and
does the same amount of work over both of the other paths.
In part (b), I don't know what is meant by "df/dt for F"...
In part (c), you're asked to find the work over the 2 parts (call them
and
) of the given path. Using the fundamental theorem makes this trivial:

