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3 years ago

Don't understand 16d at all really need help ASAP

Mathematics

2 answers:

Dominik [7]3 years ago

8 0

An inequality is with the >, <, or the =....... SO, initial one time reservation, you add onto the fee. 75 dollars each time, you pair that with c.
HOW IT SHOULD LOOK:

50(at the start) + 75c(the money charged for each cleaning) ≤ B

THE REASON WHY: the maximum budget is pretty much all you can spend, so the cost of the cleaning, as it says in the LAST LINE.... should not be over the budget, but can be under.... so we use the less than or equal to sign.
C is the number of leaning, 75 is the money charged for each cleaning, 50 is the initial cost of joining, and it should be added as part of the money you spent on the cleaning company....
and that's it

viva [34]3 years ago

3 0

The letters represent the numbers u don't know yet I don't really know how to explain it (but I know how to write it) so ill give you the answer for the inequality(question to represent the problem) it is simple is 5 plus 75C =B hope this is helpful

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Which spinner could not be used to simulate a baby being born male or female. a spinner 2 equal section. A spinner with 3 equal

sashaice [31]

Never gonna give you up

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2 years ago

Read 2 more answers

Power Series Differential equation

KatRina [158]

The next step is to solve the recurrence, but let's back up a bit. You should have found that the ODE in terms of the power series expansion for $y$

$\displaystyle\sum_{n\ge2}\bigg((n-3)(n-2)a_n+(n+3)(n+2)a_{n+3}\bigg)x^{n+1}+2a_2+(6a_0-6a_3)x+(6a_1-12a_4)x^2=0$

which indeed gives the recurrence you found,

$a_{n+3}=-\dfrac{n-3}{n+3}a_n$

but in order to get anywhere with this, you need at least three initial conditions. The constant term tells you that $a_2=0$ , and substituting this into the recurrence, you find that $a_2=a_5=a_8=\cdots=a_{3k-1}=0$ for all $k\ge1$ .

Next, the linear term tells you that $6a_0+6a_3=0$ , or $a_3=a_0$ .

Now, if $a_0$ is the first term in the sequence, then by the recurrence you have

$a_3=a_0$
$a_6=-\dfrac{3-3}{3+3}a_3=0$
$a_9=-\dfrac{6-3}{6+3}a_6=0$

and so on, such that $a_{3k}=0$ for all $k\ge2$ .

Finally, the quadratic term gives $6a_1-12a_4=0$ , or $a_4=\dfrac12a_1$ . Then by the recurrence,

$a_4=\dfrac12a_1$
$a_7=-\dfrac{4-3}{4+3}a_4=\dfrac{(-1)^1}2\dfrac17a_1$
$a_{10}=-\dfrac{7-3}{7+3}a_7=\dfrac{(-1)^2}2\dfrac4{10\times7}a_1$
$a_{13}=-\dfrac{10-3}{10+3}a_{10}=\dfrac{(-1)^3}2\dfrac{7\times4}{13\times10\times7}a_1$

and so on, such that

$a_{3k-2}=\dfrac{a_1}2\displaystyle\prod_{i=1}^{k-2}(-1)^{2i-1}\frac{3i-2}{3i+4}$

for all $k\ge2$ .

Now, the solution was proposed to be

$y=\displaystyle\sum_{n\ge0}a_nx^n$

so the general solution would be

$y=a_0+a_1x+a_2x^2+a_3x^3+a_4x^4+a_5x^5+a_6x^6+\cdots$
$y=a_0(1+x^3)+a_1\left(x+\dfrac12x^4-\dfrac1{14}x^7+\cdots\right)$
$y=a_0(1+x^3)+a_1\displaystyle\left(x+\sum_{n=2}^\infty\left(\prod_{i=1}^{n-2}(-1)^{2i-1}\frac{3i-2}{3i+4}\right)x^{3n-2}\right)$

4 0

3 years ago

5. Write an equation for a line with a slope of -4 and goes through the point (5, -1). Show all work.

Artyom0805 [142]

Answer:

y=-4x+19

Step-by-step explanation:

Plug into point-slope formula

y-y1=m(x-x1)

y-(-1)=-4(x-5)

y+1=-4x+20

-1 -1

y=-4x+19

4 0

3 years ago

2.35729166667 Written as a whole number?

Mama L [17]

hey it can be written as whole no

3 0

2 years ago

Area of a parallelogram of base 10cm and height4cm

LekaFEV [45]

The formula for finding the area of a parallelogram is-
A=b*h Where A=Area b=base length h=height
A=10*4
A=40

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3 years ago