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3 years ago

Find the simplified product where mc001-1. Jpg: mc001-2. Jpg mc001-3. Jpg mc001-4. Jpg mc001-5. Jpg mc001-6. Jpg.

SAT

2 answers:

Rufina [12.5K]3 years ago

5 0

Answer: The answer is C

-3/4pie

Explanation:

EDG 2022

sveticcg [70]3 years ago

4 0

The simplified expression, we can see that the product of the radical function is $-30 \sqrt{2x^5}\\$

<h3>Radical functions</h3>

Given the radical function

$2\sqrt{5x^3}(-3\sqrt{10x^2} )$

<h3>Take the product of the function</h3>

This can be simplified as shown:

$=2(-3)\sqrt{5(10)} \times \sqrt{x^3\cdot x^2}\\ =-6\sqrt{50}\cdot \sqrt{x^5}\\= -6(5)\sqrt{2} \sqrt{x^5}\\=-30\sqrt{2x^5}$

From the simplified expression, we can see that the product of the radical function is $-30 \sqrt{2x^5}\\$

Learn more on product of radical function here: brainly.com/question/8952483

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3 years ago

Describe and explain the difference in muscularity between the crop and the gizzard

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The difference in muscularity between the crop and the gizzard earthworm is that; Crop muscularity is soft while for gizzard it is hard.

<h3>What are the differences in Muscularity?</h3>

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2 years ago

Determine the formula weight of ca(no₃)₂. provide an answer to two decimal places.

Ronch [10]

The formula weight of $Ca(NO_3)_2$ is equal to 136.02 g/mol.

The formula weight of a chemical compound is calculated by adding the atomic masses of each chemical element contained in the compound, while multiplying them by the number of atoms respectively.

From the periodic table, the atomic mass of each chemical element is:

Carbon = 12.0107 u

Nitrogen = 14.0067 u

Oxygen = 15.999 u

Formula weight of $Ca(NO_3)_2$ = $12.0107 + [14.0067+ (15.999 \times3)]\times 2$

$F = 12.0107 + [14.0067+ 47.997] \times 2\\\\F = 12.0107 + 124.0074$

F = 136.02 g/mol.

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3 years ago