Answer:
133 fishes
Step-by-step explanation:
Units of food A = 400 units
Units of food B = 400 units
Fish Bass required 2 units of A and 4 units of B.
Fish Trout requires 5 units of A and 2 units of B.
i. For food A,
total units of food A required = 2 + 5
= 7 units
number of bass and trout that would consume food A = 2 x 
= 114.3
number of bass and trout that would consume food A = 114
ii. For food B,
total units of food B required = 4 + 2
= 6 units
number of bass and trout that would consume food B = 2 x 
= 133.3
number of bass and trout that would consume food B = 133
Thus, the maximum number of fish that the lake can support is 133.
Easy!
You take the total number of students (55) then you remove the people that only like math and remove the people that only like English and remove the people that like none of them and what’s left is how many like both subjects.
55-15-18-5=17 students that like both subjects!
Answer:
207 m
Step-by-step explanation:
17 x 6 = 102
15 + 6 = 21
5 x 21 = 105
105 + 102 = 207 m^2
Answer: x^2 + 19
Step-by-step explanation: Cancel out x^2 and add 7 and 12 together. 7 + 12 = 19. Next plug in x^2. So, its now x^2 + 19.
Hope this help!