Answer: 0.86 of the exam scores are between 68 and 77.99 points
Step-by-step explanation:
Since the set of computer science exam scores are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = computer science exam scores .
µ = mean score
σ = standard deviation
From the information given,
µ = 71.33 points
σ = 3 points
We want to find the proportion of the exam scores are between 68 and 77.99 points. It is expressed as
P(68 ≤ x ≤ 77.99)
For x = 68,
z = (68 - 71.33)/3 = - 1.11
Looking at the normal distribution table, the probability corresponding to the z score is 0.13
For x = 68,
z = (77.99 - 71.33)/3 = 2.22
Looking at the normal distribution table, the probability corresponding to the z score is 0.99
P(68 ≤ x ≤ 77.99) = 0.99 - 0.13 = 0.86
Answer:
0.375
Step-by-step explanation:
Answer:
The correct option is C). When it was purchased, the coin was worth $6
Step-by-step explanation:
Given function is f(t)=
Where t is number of years and f(t) is function showing the value of a rare coin.
A figure of f(t) shows that the graph has time t on the x-axis and f(t) on the y-axis.
Also y-intercept at (0,6)
hence, when time t was zero, the value of a rare coin is 6$
f(t)=
f(0)=
<em>f(0)=6</em>
Thus,
The correct option is C). When it was purchased, the coin was worth $6
Answer:
I think the answer to question 1 is c = x($7) + y($5)
12/3 = x/8
Cross multiply
3x = 96
Eliminate
3x/3 = 96/3
x = 32