He starts saving $ in January to buy a gift in June. (which is 6 months, or 5 months not including June)
Each month he saves 2/3 of his allowance, which is $14.
[his allowance each month is $21, 2/3 of his allowance is $14]
(you multiply 21 by 2/3 = 42/3 = 14)
The gift he wants to buy is $110
x = the number of months
y = total cost
14x = y
14x = 110 [he saves $14 each month, he wants to have a total of $110 to buy a gift]
Plug in 6 for x in the equation
14(6) = 110
84 = 110 (He is $26 short, so saving either for 5 or 6 months will not get Ian $110)
Ian will not have enough money because he is $26 short for 6 months or $40 short for 5 months. (you can decide whether you want to go by 5 months or 6(including June), sorry for the confusing answer)
Step-by-step explanation:
Since equivalent fractions do not always have the same numerator and denominator, one way to determine if two fractions are equivalent is to find a common denominator and rewrite each fraction with that denominator. Once the two fractions have the same denominator, you can check to see if the numerators are equal.
The answer should be 4x+ 17 > x - 1
The answer is B
The formula is 1/6(pie)diameter^3
Do you have the inequalities and graphs/options?