Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by
In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
The relationship between 1’s in the value of 911, 147, 835
shows their numerical order in the number. In which to further elaborate we
shall break down the number into its expanded form and word form:
<span><span>1. </span>900, 000,
000 = nine hundred million</span>
10, 000, 000 = ten million
1, 000, 000 = one million
100, 000 = one hundred thousand
40, 000 = forty thousand
7, 000 = seven thousand
800 = eight hundred
30 = thirty
5 = five
<span><span>2. </span><span> Nine hundred eleven million one hundred
forty-seven thousand eight hundred and thirty five. </span></span>
Answer:
none of the above the 7^8/8 is equivalent to
Trapezoid ABCD was the original figure for trapezoid A'B'C'D. They are similar because they are the same shape, Trapezoid A'B'C'D is slightly bigger or smaller because it was dilated from trapezoid ABCD.
Answer:
it must be number 1
I am sure about parallel side and 4 right angles
