A wireless ________ extender is a network device that enhances transmission of your wireless signal.

Given a sorted list of integers, output the middle integer. A negative number indicates the end of the input (the negative numbe

masya89 [10]

Answer:

The program in Python is as follows:

myList = []

num = int(input())

count = 0

while num>=0:

myList.append(num)

count+=1

num = int(input())

myList.sort()

mid = int((count-1)/2)

print(myList[mid])

Explanation:

This initializes the list

myList = []

This gets the first input

num = int(input())

This initializes count to 0

count = 0

The following is repeated until the user inputs a negative number

while num>=0:

This appends the input number to the list

myList.append(num)

This increments count by 1

count+=1

This gets another input

num = int(input())

This sorts the list

myList.sort()

Assume the number of inputs is odd, the middle element is calculated as

mid = int((count-1)/2)

This prints the middle element

print(myList[mid])

From the complete question. the condition that ends the loop is a negative integer input

8 0

3 years ago

Brian has created the following selection sort class in Java. In which line is the index of the smallest value returned? In whic

katen-ka-za [31]

Answer:

Explanation:

Since there are no line numbers in this question I will start counting from public class SelectionSort{ as line 1 and so on, as well as provide the code on that line.

The index of the smallest value is returned on line 8 where it says return min which shouldn't have any spaces and should be return minPosition;

The input array is given as an argument at the beginning of the function on line 2 where it says private static int positionMin (int] vals, int startPosition) {, as the variable vals.

This input array is also used as an argument on line 10 where it says Position; private static void swap(int] vals, int firstPosition, int secondPosition) and line 15 where it says vals[secondPosition] temp return public static void selSort(int| vals) {

8 0

3 years ago

Why are coders using encoder software? What are their advantages and disadvantages? And when might a coder need to use the codin

IrinaVladis [17]

Coders using encoder software:
To enhance their productivity
Speed and Efficiency
Accuracy and consistency

Encoding is done to reduce the number of bit to be transmitted and save bandwidth .can be fairly complex and contain some delicate parts. This makes them less tolerant of mechanical abuse and restricts their allowable temperature.

including increased productivity, accuracy, and efficiency in coding and the consistent application of coding rules. However, there is a cost to the software, but savings can be seen in other areas.

7 0

3 years ago

Document design techniques make your document easier for readers to skim. Therefore, these techniques give your writing "High Sk

USPshnik [31]

Document design techniques that make your document easier for readers to skim and therefore gives your writing "High Skim Value" is true. The answer is letter A. Documents that give you a high skim value are the headings and subheadings, white space and the toposgraphy.

3 0

3 years ago

Create a macro named mReadInt that reads a 16- or 32-bit signed integer from standard input and returns the value in an argument

timofeeve [1]

Answer:

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

Explanation:

For an assembly code/language that has the conditions given in the question, the program that tests the macro, passing it operands of various sizes is given below;

;Macro mReadInt definition, which take two parameters

;one is the variable to save the number and other is the length

;of the number to read (2 for 16 bit and 4 for 32 bit) .

%macro mReadInt 2

mov eax,%2

cmp eax, "4"

je read2

cmp eax, "2"

je read1

read1:

mReadInt16 %1

cmp eax, "2"

je exitm

read2:

mReadInt32 %1

exitm:

xor eax, eax

%endmacro

;macro to read the 16 bit number, parameter is number variable

%macro mReadInt16 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;macro to read the 32 bit number, parameter is number variable

%macro mReadInt32 1

mov eax, 3

mov ebx, 2

mov ecx, %1

mov edx, 5

int 80h

%endmacro

;program to test the macro.

;data section, defining the user messages and lenths

section .data

userMsg db 'Please enter the 32 bit number: '

lenUserMsg equ $-userMsg

userMsg1 db 'Please enter the 16 bit number: '

lenUserMsg1 equ $-userMsg1

dispMsg db 'You have entered: '

lenDispMsg equ $-dispMsg

;.bss section to declare variables

section .bss

;num to read 32 bit number and num1 to rad 16-bit number

num resb 5

num1 resb 3

;.text section

section .text

;program start instruction

global _start

_start:

;Displaying the message to enter 32bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg

mov edx, lenUserMsg

int 80h

;calling the micro to read the number

mReadInt num, 4

;Printing the display message

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Printing the 32-bit number

mov eax, 4

mov ebx, 1

mov ecx, num

mov edx, 4

int 80h

;displaying message to enter the 16 bit number

mov eax, 4

mov ebx, 1

mov ecx, userMsg1

mov edx, lenUserMsg1

int 80h

;macro call to read 16 bit number and to assign that number to num1

;mReadInt num1,2

;calling the display mesage function

mov eax, 4

mov ebx, 1

mov ecx, dispMsg

mov edx, lenDispMsg

int 80h

;Displaying the 16-bit number

mov eax, 4

mov ebx, 1

mov ecx, num1

mov edx, 2

int 80h

;exit from the loop

mov eax, 1

mov ebx, 0

int 80h

7 0

3 years ago