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monitta
3 years ago
6

A small boat leaves a port town and travels due north for 7.4 miles and then turns due east for 3.6 miles

Mathematics
1 answer:
posledela3 years ago
4 0

11 miles far does the boat travel

Step-by-step explanation:

hope it helps

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The following statement is false. Rewrite the statement to make it true.
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that's why this statement is false

so, true statement can be written as

The are six terms in the series equation.........Answer

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charle [14.2K]

Answer:

17-18) Can you type out the questions for 17-19, I can't read them.

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Simplify 4^-4.<br> please help I have 10 minutes
kolezko [41]

Answer:

1/256

Step-by-step explanation:

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7 0
3 years ago
The volume of a right circular cone is latex: v=\frac{1}{3}\pi r^2h v = 1 3 π r 2 h . suppose a cone has a constant height of h
MrRa [10]

V  =  (1/3)·π·r²·h                     First, multiply both sides by 3:

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7 0
4 years ago
Need help solving quadratic equations
Semenov [28]
--------------------------------------------------------------------
Question
--------------------------------------------------------------------
3x = 0.5x²

--------------------------------------------------------------------
Take out common factor , i.e. x
--------------------------------------------------------------------
3x = 0.5x²
3x - 0.5x² = 0
x(3 - 0.5x) = 0 

--------------------------------------------------------------------
Use the Zero Product Property to solve for x
--------------------------------------------------------------------
x(3 - 0.5x) = 0
x = 0 or 3 - 0.5x = 0
x = 0 or 0.5x = 3
x = 0 or x = 3 ÷ 0.5
x = 0 or x = 6

--------------------------------------------------------------------
Answer: x = 0 or 6 (Answer D)
--------------------------------------------------------------------


--------------------------------------------------------------------
Question
--------------------------------------------------------------------
0 = 5x² - 2x + 6

--------------------------------------------------------------------
Use Quadratic Formula
--------------------------------------------------------------------
x =  \frac{-b\pm  \sqrt{b^2-4ac} }{2a}

a = 5, \ b = -2, \ c = 6

x =  \frac{-(-2)\pm  \sqrt{(-2)^2-4(5)(6)} }{2(5)}

x =  \frac{2\pm  \sqrt{-116} }{10}

x = \frac{2\pm \sqrt{-4} \sqrt{29}  }{10}

x = \frac{2\pm  2i\sqrt{29} }{10}

x = \frac{1\pm i\sqrt{29} }{5}

--------------------------------------------------------------------
Answer \ = \boxed { \boxed { x = \frac{1\pm i\sqrt{29} }{5}}}
--------------------------------------------------------------------



8 0
4 years ago
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