A small boat leaves a port town and travels due north for 7.4 miles and then turns due east for 3.6 miles

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

Write an expression to show the sum of fourteen and triple eight.

katrin [286]

14x8³

have a good day!! :)
hope this helps!!! :D
plz give brainliest!! XD

8 0

3 years ago

Diego measured the length of a pen to be 21 cm. The actual length of the pen is 23 cm. Which of these is closest to the percent

Colt1911 [192]

B hope it helps you

4 0

3 years ago

Please answer this if you can thank you :))

krek1111 [17]

Answer:

The variable that has the highest power is considered to be the degree of polynomials in an algebraic equation.

A column:

1) $4x^3$ .

The degree is 3.

2) $x^2+4$ .

The degree is 2.

3) $x-2$

The degree is 1.

B column:

1) $2x^2+1$

The degree is 2.

2) $x^2-x$

The degree is 2.

3) $x^3-5x^2+1$

The degree is 3.

A×B columns:

While Multiplying two terms in a equation, if the variables are same then multiply the constant value and sum the exponent value.

1) $(4x^3)(2x^2+1)$ .

= $8x^5+4x^3.$

The degree is 5.

2) $(x^2+4)(x^2-x)$ .

= $x^4-x^3+4x^2-4x$ .

The degree is 4.

3) $(x-2)(x^3-5x^2+1)$ .

$=x^4-5x^3+x-2x^3+15x^2-3.\\=x^4-7x^3+15x^2+x-3.$

The degree is 4.

3 0

3 years ago

What is the equation of this line? A. Y=1/2 x B.y=-1/2 x C.-2 x Y= 2x

sp2606 [1]

The correct answer is is y=2x

7 0

3 years ago